<u>Answer:</u> The equilibrium partial pressure of nitrogen gas, oxygen gas and nitrogen dioxide are 0.7934 atm, 0.1668 atm and 0.0332 atm respectively.
<u>Explanation:</u>
We know that:
Partial pressure of nitrogen gas at 2200°C = 0.81 atm
Partial pressure of oxygen gas at 2200°C = 0.20 atm
The chemical equation for the formation of nitrogen dioxide follows:

<u>Initial:</u> 0.81 0.20
<u>At eqllm:</u> 0.81-x 0.20-2x 2x
The expression of
for above equation follows:

We are given:

Putting values in above equation, we get:

Neglecting the negative value of 'x' because partial pressure cannot be negative
So, equilibrium partial pressure of nitrogen dioxide = 2x = 2(0.0166) = 0.0332 atm
Equilibrium partial pressure of nitrogen gas = (0.81 - x) = (0.81 - 0.0166) = 0.7934 atm
Equilibrium partial pressure of oxygen gas = (0.20 - 2x) = [0.20 - 2(0.0166)] = 0.1668 atm
Hence, the equilibrium partial pressure of nitrogen gas, oxygen gas and nitrogen dioxide are 0.7934 atm, 0.1668 atm and 0.0332 atm respectively.