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3 years ago

Calculate the volume of an object (in mL) if the density of the object is 4.08 g/mL and the mass of the object is 10.02 g.

Chemistry

1 answer:

slega [8]3 years ago

6 0

Answer:

<h2>The answer is 2.5 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass of object = 10.02 g

density = 4.08 g/mL

The volume of the object is

$volume = \frac{10.02}{4.08} \\ = 2.4558823...$

We have the final answer as

<h3>2.5 mL to one decimal place</h3>

Hope this helps you

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Gennadij [26K]

Answer:

When two substances that are of different temperatures are brought together and there is heat transfer such that the substances come to thermal equilibrium, the effect on the particle motion are as follows

1) The particle motion of the hotter body reduces, because its temperature reduces

2) The particle motion of the colder body increases, because its temperature increases

3) For gases, the volume and or pressure reduces for the hotter body, and if the temperature of the gas falls below the boiling point temperature, the gas will change into liquid

For the colder gas, only the volume and or pressure increases and the temperature rises

4) For liquids, if the temperature of the hotter liquid falls below the melting point, the hotter liquid will become a frozen solid

For the the colder liquid, if the temperature is raised above the boiling point, the liquid changes into gas and the temperature does not rise above the boiling point temperature, until all the cold liquid has evaporated

5) For solids, the vibration of the particles of the hotter substance reduces and the solid becomes more brittle

For the colder body, the rise in temperature causes an increase in vibration of the particles, and if the temperature rises above the melting point, the colder solid will begin to melt

Explanation:

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3 years ago

How many moles of PbCl2 are produced

KengaRu [80]

Answer:21 moles of PbCl2 formed

Explanation: 3Pb(NO3)2(aq) + 2AlCl3(aq) --> 3PbCl2(s) + 2Al(NO3)3(aq)

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8 0

3 years ago

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The theater director offered every member of the drama one vote for which play they preferred to perform. The director found tha

irakobra [83]

<h2>ANSWER:</h2>

Yes, in this group both events "Oddems Family" and "Thirteenth Night" are mutually exclusive.

<h3>Explanation:</h3>

Mutually exclusive is an statistical term which means the probability of occurrence of two separate event at the same time is zero. It means two events can not be occurred simultaneously.

For example, if we roll the deck ant the probability of coming 1 and 6 at the same time is zero and both events do not depends upon each others occurrence.

Hence only one drama can run in theater at one time. So they are mutually exclusive events.

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3 years ago

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1. How would the series of figures change in the presence of a catalyst?

statuscvo [17]

No, it won't change the amount of reactants nor the products as a catalyst will only provide an alternative path where lower activation energy is needed for the process to take place.

hope this explains it

If it does, please give it a brainliest :)))

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3 years ago

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What is the molecular mass for a non-electrolyte if 35.0 g of it is dissolved in 45.0 grams of water and the solutions boiling p

adelina 88 [10]

The boiling point of water increases as the amount of impurities dissolved in it increases. For our purposes, we will consider the non-electrolyte to be the dissolved impurity. The change in the boiling point can be calculated using the equation:

$\Delta T_b = i \times K_b \times m$

where $\Delta T_b$ is the change in boiling point, $i$ is the van ‘t Hoff factor (whose value denotes the number of particles each formula unit of the dissolved substance dissociates into in water), $K_b$ is the boiling point elevation constant, and $m$ is the molality (moles of solute/kilogram of solvent) of the solution.

Right off the bat, since we're dealing with a non-electrolyte, the dissolved substance can be assumed not to dissociate in water. So, our van ‘t Hoff factor, $i$ , would be 1 (by contrast, the $i$ for an ionic compound like NaCl would be 2 since, in water, NaCl would dissociate into two particles: one Na⁺ ion and one Cl⁻ ion). We're also given our $K_b$ , which is 0.51 °C/<em>m</em>.

Assuming the normal boiling point of pure water to be 100 °C (a defined value for sig fig purposes), the change in boiling point from having dissolved 35.0 g of the non-electrolyte can be obtained by subtracting 100 °C from the final—elevated—boiling point of 101.25 °C:

$\Delta T_b = 101.25\text{ }^o\text{C} - 100\text{ }^o\text{C} = 1.25\text{ }^o\text{C}$

Now, recall what we're asked to determine: the molecular mass of the dissolved substance. There is one unknown left in the equation: the molality of the solution. Let's first solve for that:

$m = \frac{\Delta T_b}{K_b} = \frac{1.25^\text{ o}\text{C}}{0.51^\text{ o}\text{C}/m} \\ m = 2.45 \text{ mol solute/kg water}.$

Notice that we didn't include the <em>i </em>since its value is 1.

Now, what would happen if we multiplied our molality by the mass of water we've been given? We would be left with the moles of solute. And what are we asked to find? The molecular mass, or the mass per mole. We can accomplish this in two steps. Remember to convert your mass of water to kilograms:

$2.45 \text{ mol solute/kg water} \times 0.045 \text{ kg water} = 0.110 \text{ mol solute.}$

And, finally, we divide the mass of our solute by the number of moles of solute:

$\frac{35.0 \text{ g solute}}{0.110 \text{ mol solute}} = 317.5 \text{ g/mol}$

Our answer to two significant figures (which is the number of sig figs to which our $K_b$ is given) would be 320 g/mol.

5 0

3 years ago