Answer:
The answer to your question is 2.21 %
Explanation:
Data
mass of Na₂SO₄ = 10.9 g
mass of H₂O = 482 g
Formula
Percent by mass = x 100
Substitution
x 100
Simplification and result
x 100
Percent by mass = 0.022 x 100
Percent by mass = 2.21
Here we have to draw the four isomers of the compound 3-bromo-4-fluorohexane.
The four isomers of the compound is shown in the figure.
In an organic molecule the chiral -C center is that where four (4) different groups are present. In 3-bromo-4-fluorohexane the 3 and 4 positions are chiral centers. The possible isomers of a molecule can be obtained from the formula 2n. As here 2 chiral centers are present thus number of stereoisomers will be 2×2 = 4.
The four different isomers as shown in the figure are 3R-, 4R-; 3S-, 4S; 3R, 4S and 3S-, 4R- 3-bromo-4-fluorohexane.
In the 3-bromo-4-fluorohexane the functional groups are -Br, C₂H₅, -C₃H₆F and -H for 3-position and -F, -C₂H₅, -C₃H₆ and -H for 4-position respectively.
The priority of the -3 position will be Br > C₃H₆F > C₂H₅ > H and for -4 position F > C₃H₆Br > C₂H₅ > H. If the rotation from the higher priority group to lower is clockwise and anticlockwise then the S- and R- notation are used respectively. However if the -H atom is present at the horizontal position then the notation will be reverse.
Thus the four isomers of the compound is shown.
Explanation:
The reaction equation will be as follows.
Calculate the amount of dissolved as follows.
It is given that = 0.032 M/atm and
=
atm.
Hence, will be calculated as follows.
=
=
=
or, =
It is given that
As,
=
=
Since, we know that pH =
So, pH =
= 5.7
Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.