Answer:
y = x + 3y = x - 1
Step-by-step explanation:
Just graph them!
Hope I could help.
Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
Answer:
not an answer but how do you attach images because it would be more useful
Step-by-step explanation:
Answer:
y = -3 m = -1 b = 3
Step-by-step explanation:
-3y=3x-9
To isolate the y variable, divide both sides by -3.
y = -1x + 3
y = -3
m = -1
b = 3
Answer:
-5 because the number is before zero which irrational number