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abruzzese [7]
3 years ago
9

I'm not sure how to do this. HELP

Mathematics
2 answers:
Anit [1.1K]3 years ago
8 0
The answer is C to this question
maxonik [38]3 years ago
8 0
I think the answer is A because all you doing is adding and then divide i believe 

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Question 6, name the angle pair 5 and 8<br> (In picture)
rodikova [14]

Answer:

Linear, Corresponding, and Vertical

Step-by-step explanation:

5 and 8 would have the same degree. So would 1 and 4, and 2 and 3, and 6 and 7 (lot's of "and's" because it's lots of the same degrees...)

7 0
3 years ago
Solve the following equation to determine the value of x: 3x + (x + 10) + 5x + (2x + 2) = 56
nika2105 [10]

Answer:

I think x = 4.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x + x +10 + 5x + 2x + 2 =56

(3x + x + 5x + 2x) + (10 + 2) = 56 (Combine Like Terms)

11x + 12 = 56

11x + 12 = 56

Step 2: Subtract 12 from both sides.

11x + 12 − 12 = 56 − 12

11x = 44

Step 3: Divide both sides by 11.

11x/11 = 44/11

x = 4

7 0
3 years ago
During a musical an orchestra is playing. As the music plays, the volume changes in the beginning of the piece can be modeled by
Alja [10]

Answer:

The numbers of measure of music played are 1 and 7

Step-by-step explanation:

Given

s = 10|x - 4| + 50

Required

Solve for x when s = 80

Substitute 80 for x

80 = 10|x - 4| + 50

Subtract 50 from both sides

80 - 50= 10|x - 4| + 50 - 50

30= 10|x - 4|

Divide through by 10

\frac{30}{10}= \frac{10|x - 4| }{10}

3= |x - 4|

Reorder

|x - 4| = 3

This can be split into

x - 4 = 3 or x - 4 = -3

Solve for x

x = 4 + 3 or x = 4 - 3

x = 7 or x = 1

Hence:

<em>The numbers of measure of music played are 1 and 7</em>

4 0
3 years ago
The function f(x)=x√3 has a domain of (−∞,∞) and a range of [0,∞)<br><br> True<br><br> False
Vlad [161]
True I’m not sure I’m just guessing cause I gotta answer Two questions before mine
7 0
3 years ago
Solve for x............
Yanka [14]

Step-by-step explanation:

because angle A and C are similar, so

9x-8=28

9x=36

x=4

5 0
3 years ago
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