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Harman [31]
3 years ago
15

10 is 40% of what number?

Mathematics
1 answer:
JulijaS [17]3 years ago
5 0
Hello, 

x* \frac{40\%}{100\%}=10\\\\ x= \frac{10*100}{40}  \\  \\ \boxed{x=25}
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Which of the following tables is a relation that represents a function?
uysha [10]
The first one is not a function due to the rule that there can not be more than one x, such as there is a repeated number 1 , 2 , 1 , 4  There should not be two
x = 1 terms.

Same the same rule applies to the second option as well as the last.

Your answer is C. or the third option
x= 6, 5, 4, 1
y=6, 4, 6, 2

Hope this Helps
3 0
2 years ago
A carton of paper is priced at 27.00 now if the paper goes on sale for 25% off the current price what will be the sale price of
hjlf

Okay, to solve this we simply find 75% of the carton of paper, because 100%-25% = 75%

0.75(27) = 20.25

The carton of paper costs $20.25

4 0
2 years ago
The price of an Ice cream cone is $3.25, but it cost $3.51 with tax. What is the sales tax rate?
Mekhanik [1.2K]

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8 0
2 years ago
Read 2 more answers
What is the answer to -1 5/8 × 2 2/3
Yuri [45]

Answer: -13/3

Step-by-step explanation: -1  5/8  -> -13/8        2  2/3->  8/3

-13/8 x 8/3 = -104/24

                  = -13/3  OR  -4   1/3      

5 0
2 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are
almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = <u><em>the number that are not correctly calibrated.</em></u>

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_3

So, the required probability = \frac{^{6}C_3}{^{8}C_3}  

                                              = \frac{20}{56}  = <u>0.35</u>

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_2

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_1

So, the required probability = \frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}  

                                                = \frac{30}{56}  = <u>0.54</u>

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_1

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_2

So, the required probability = \frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}  

                                                = \frac{6}{56}  = <u>0.11</u>

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0
3 years ago
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