Write an equation of the line that passes through (0,-5) and is perpendicular to the line y=4/5x.

Mathematics

1 answer:

Illusion [34]2 years ago

3 0

Answer:

y = -5/4x - 5

Step-by-step explanation:

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Please help me with this please and thank you

Ierofanga [76]

Step-by-step explanation:

a geometric sequence means that every term is created by multiplying the previous term by a certain constant factor. this factor is called the "common ratio".

so,

6×r = 18

r = 18/6 = 3

and a quick check tells us this works also for the next terms (18×3 = 54, 54×3 = 162), so it is indeed a geometric sequence with common ratio 3.

a0 = 6

a1 = a0 × 3 = 6×3 = 18

a2 = a1 × 3 = a0 × 3×3 = 6×3² = 54

an = a0 × 3^n = 6 × 3^n

so,

f(x) = 6×3^x, x is integer, x >=0

4 0

1 year ago

PLEASE HELP ASAP Solve. y > 2x + 2 y ≤ -3/2 x - 5

Fynjy0 [20]

$2x + 2 < - \frac{3}{2} x - 5 \\ 2x + \frac{3}{2} x < - 5 - 2 \\ 3.5x < - 7 \\ x< - 2$
$x < - 2 \\ x < \frac{y - 2}{2}$
$-2 = \frac{y - 2}{2} \\ y=-2$

7 0

2 years ago

A sailboat leaves port and sails 12 kilometers west and then 9 kilometers north.

GarryVolchara [31]

Answer: The sailboat is at a distance of 15 km from the port.

Step-by-step explanation: Given that a sail boat leaves port and sails 12 kilometers west and then 9 kilometers north.

We are to find the distance between the sailboat from the port in kilometers.

Since the directions west and north are at right-angles, we can visualize the movement of the sailboat in the form of a right-angled triangle as shown in the attached figure.

The sailboat moves leaves the port at P and reach O after sailing 12 km west. From point O, again it moves towards north 9 km and reach the point S.

PS = ?

Using the Pythagoras theorem, we have from right-angled triangle SOP,

Thus, the sailboat is at a distance of 15 km from the port.