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kicyunya [14]
3 years ago
15

What is the equation of the line that passes through (-3, -1) and has a slope of 2/5 ? Put your answer in slope-intercept form.

Mathematics
2 answers:
Scrat [10]3 years ago
8 0

Answer:

  a.  y = 2/5x + 1/5

Step-by-step explanation:

In point-slope form, the equation of a line with slope m through point (h, k) can be written

  y = m(x -h) +k

Then a line with slope 2/5 through the point (-3, -1) will have point-slope equation ...

  y = (2/5)(x +3) -1

This can be simplified to the desired form:

  y = 2/5x +6/5 -1 . . . . . . eliminate parentheses; next, collect terms

  y = 2/5x + 1/5

Nesterboy [21]3 years ago
6 0
I don’t know what the answer is I need some help
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How many feet are in 333 miles?
zheka24 [161]

Answer:

1,758,240 Feet

Step-by-step explanation:

1 Mile = 5280 Feet

333 Miles = 1,758,240 Feet

6 0
3 years ago
A positive integer is 47 more than 9 times another. Their product is 1860. Find the two integers.
svlad2 [7]
X = 47 + 9y
xy = 1860

y(47 + 9y) = 1860
47y + 9y² = 1860
9y² + 47y - 1860 = 0

> using a quadratic equation solver on a calculator but you can also use the quadratic equation = [-b+/- √(b²-4ac)]/(2a)
> only integer solution is x = 12

12y = 1860
y = 155

integers are 12 and 155


8 0
3 years ago
Find the distance between the pair of points: (6,−3) and (1,0
rosijanka [135]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

\sqrt{34}

»»————- ★ ————-««  

Here’s why:

⸻⸻⸻⸻

\text{\underline{The distance formula is:}}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⸻⸻⸻⸻

\boxed{\text{Calculating the answer....}}\\\\d = \sqrt{(1-6)^2+(0-(-3))^2}\\--------------\\\rightarrow d = \sqrt{(-5)^2+(3)^2}\\\\\rightarrow d = \sqrt{(25+9)}\\\\\rightarrow d =\boxed{ \sqrt{34} }

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.

6 0
3 years ago
Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy cla
My name is Ann [436]

Answer: Choice C

Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.

======================================================

Explanation:

Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.

Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.

Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.

-----------------

In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.

Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.

8 0
3 years ago
Help ASAP!!!!!! 20 points!!
nekit [7.7K]

Answer:

Hey there!

\frac{3+2-4^2(7)-5+2}{16-6(6)^2}

\frac{3+2-16(7)-5+2}{16-6(36)}

\frac{3+2-112-5+2}{16-216}

\frac{-110}{-200}

\frac{11}{20}

Let me know if this helps :)

7 0
3 years ago
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