I think it is the 3rd one but I might be wrong...
Hopes this helps:
Answer: -3/8
Have a great day.
Answer:
a. 129 meters
Step-by-step explanation:
The given parameters of the tree and the point <em>B</em> are;
The horizontal distance between the tree and point <em>B</em>, x = 125 meters
The angle of depression from the top of the tree to the point <em>B</em>, θ = 46°
Let <em>h</em> represent the height of the tree
The horizontal line at the top of the tree that forms the angle of depression with the line of sight from the top of the tree to the point <em>B</em> is parallel to the horizontal distance from the point <em>B</em> to the tree, therefore;
The angle of depression = The angle of elevation = 46°
By trigonometry, we have;
tan(θ) = h/x
∴ h = x × tan(θ)
Plugging in the values of the variables gives;
h = 125 × tan(46°) ≈ 129.44
The height of the tree, h ≈ 129 meters
Answer:
8a^3.
Step-by-step explanation:
(a+b)^3=a^3+b^3+3a^2b+3ab^2
(a-b)^3=a^3-b^3-3a^2b+3ab^2
(a+b)^3+(a-b)^3=2a^3+6ab^2
According to the question
(a+b)^3+(a-b)^3+6a(a^2-b^2)
Put in the value
=2a^3+6ab^2 +6a^3–6ab^2
=8a^3
