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den301095 [7]
3 years ago
9

Convert 512 into binary numbers​

Mathematics
1 answer:
ra1l [238]3 years ago
7 0

Answer:

Step by step

512 = 2 ^ 9

That translates into 1 followed by 9 zeros.

units = 0

2      = 0

4      = 0

8      = 0

16    = 0

32    =0

64    =0

128  = 0

256 = 0

512 = 1

1 000 000 000

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mrs_skeptik [129]

Answer:

x=9

Step-by-step explanation:

17x - 12 = 114 + 3x

First  Subtract 3x from both sides

14x - 12 = 114

Add 12 to both sides

14x=126

Divide by GCF (14)

x=9

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Add or subtract the following mixed numbers using the first method. Be sure your answers are in mixed number format and reduced
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by using the first method,
multiplying 3/8 with 3/3 and 1/6 with 4/4 we get 9/24 and 4/24 so,
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Label this graph as “linear” or “nonlinear.”
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That graph would be non-linear
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PLEASE HELP MEEE
antoniya [11.8K]

Answer:

(6a-4)°=(2a+68)°

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How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

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