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3 years ago

What is the equation for the graph below?

Mathematics

1 answer:

andriy [413]3 years ago

3 0

Answer:

y=-log5(x)

Step-by-step explanation:

www!desmos!com/calculator

online graphing calculator. replace the ! for .

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Your math teacher allows you to choose the most favorable measure of central tendency of you test scores to determine your grade

Ugo [173]

To answer the question above,
If you entered your test scores correctly, then your choices are off the wall.

The median is 87 

The mode is 89 

The mean is 85.833... 

There is not a mode of 91 ! 

If you can choose, pick the mode (89).
I hope my answer helped you

8 0

3 years ago

Read 2 more answers

Melissa averages a rate of 1.5 steps per second while walking. How many steps will she take in an hour if this rate continues?

Sonbull [250]

Answer:

5400

Step-by-step explanation:

1.5×60=90 steps per min

90×60=5400 steps per hour

6 0

3 years ago

Give the number to which the Fourier series converges at a point of discontinuity of f.

quester [9]

Answer:

The Fourier series of f(x) converges to 3 at the points x= π+2kπ, where k is an integer.

Step-by-step explanation:

First, recall that the function f(x) is extended 2π periodic to the whole real line, in order to obtain a valid Fourier expansion. Remember that a Fourier series is formed by a sines and cosines, which are 2π-periodic.

So, the 2π-periodic expansion of f(x) is discontinuous at the points π+2kπ, in particular π and -π. Check the attached figure to a better understanding.

Now, the Dirichlet theorem on the convergence of a Fourier series tells us that the series converges to the function at the points of continuity, and at points of discontinuity the sum of the series is

$\frac{f(x_0+)+f(x_0-)}{2}$ .

Here we understand the notation $f(x+)$ and $f(x-)$ as

$f(x_0+) = \lim_{x\rightarrow x_0}f(x), x>x_0$

and

$f(x_0-) = \lim_{x\rightarrow x_0}f(x), x$ .

In this particular case

$f(\pi-) = \lim_{x\rightarrow \pi}(3-2x) = 3-2\pi, x$ .

For the limit $f(\pi+) = \lim_{x\rightarrow \pi}(3-2x)$ , with $x>\pi$ recall that our function is 2π-periodic, so the values of f near π, with x>π are the same when x is near -π and x>-π. Again, check the attached figure. So,

$f(\pi+) = \lim_{x\rightarrow \pi}(3-2x) = 3+2\pi, x$ .

Thus,

$\frac{f(\pi+)+f(\pi-)}{2} = \frac{3+2\pi +3-2\pi}{2} = \frac{6}{2} =3$ .

Note: In the attached figure we only have drawn three repetitions of the 2π-periodic extension of $f$ , recall that the extension is ad infinitum. Also, the points drawn in the dotted lines are the sum of the series at the points of discontinuity.