Step-by-step explanation:
so we're making two draws *with* replacement (this is important)
step 1: for the first draw, it wants the probability of getting a sour candy. to calculate this:
(# of sour candy) / (total # of candy)
step 2: for the second draw, it wants the probability of *not* getting a sour candy. to calculate this, you can calculate 1 - (the probability form part 1).
step 3: to find the probability of both events happening together, simply multiply the probabilities from part 1 and 2 together
side note: for step 2, you can only do this because the candy is being replaced. if there were no replacement, you'd have to re-calculate (# of non-sour candies) / (total after the first candy is drawn)
258 cubic inches
Since the boxes are kind of on their own—>
First box: 7*2*12 = 168
Second box: 5*2*9=90
168+90 = 258
.4 is smallest, 1/2 , then 60% is greatest.
Answer:
The 400 coupon is 80 cents better
Step-by-step explanation:
First find the sale price with the coupon
744 - 400 = 344
Now find the sale price with the discount
100-55 = 45
We will pay 45% of the original price
744*45%
744*.45
344.80
I don’t get the question? What are you trying to find?