3 years ago

What is the relationship between ∠FBE and ∠CBD?

1 answer:

4 0

Answer:

They are both 47 degrees

You might be interested in

Alchen [17]

Answer:

how to delete a question can you tell me

7 0

3 years ago

zmey [24]

Answer:

Step-by-step explanation:

7 0

3 years ago

geniusboy [140]

0.083 In decimal 8.3% in percentage

8 0

3 years ago

Lina20 [59]

Answer:

Step-by-step explanation:

6 0

4 years ago

snow_tiger [21]

$\nabla f=(xy\cos xy+\sin xy)\,\vec\imath+x^2\cos xy\,\vec\jmath$

then we should have

$\dfrac{\partial f}{\partial y}=x^2\cos xy\implies f(x,y)=x\sin xy+g(x)$

Differentiating with respect to $x$ gives

$\dfrac{\partial f}{\partial x}=xy\cos xy+\sin xy=\sin xy+xy\cos xy+g'(x)$

$\implies g'(x)=0\implies g(x)=C$

So $F$ is indeed conservative, and

$f(x,y)=x\sin xy+C$

8 0

3 years ago