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3 years ago

9) If f(x) = 2x + 1, What is f(-3)?

1 answer:

7 0

9= f (-3)= -5 It doesn't matter if you love him, or capital H-I-M
Just put your paws up 'cause you were born this way, baby
My mama told me when I was young
We are all born superstars
She rolled my hair and put my lipstick on
In the glass of her boudoir
"There's nothing wrong with loving who you are"
She said, "'Cause he made you perfect, babe"
"So hold your head up girl and you'll go far
Listen to me when I say"
I'm beautiful in my way
'Cause God makes no mistakes
I'm on the right track, baby I was born this way
Don't hide yourself in regret
Just love yourself and you're set
I'm on the right track, baby
I was born this way (born this way)
Oh there ain't no other way
Baby I was born this way
Baby I was born this way (born this way)
Oh there ain't no other way
Baby I was born this way
Right track baby I was born this way
Don't be a drag, just be a queen
Don't be a drag, just be a queen
Don't be a drag, just be a queen
Don't be, don't be, don't be
Give yourself prudence
And love your friends
Subway kid, rejoice your truth
In the religion of the insecure
I must be myself, respect my youth
A different lover is not a sin
Believe capital H-I-M (hey hey hey)
I love my life, I love this record and
Mi amore vole fe, yah (same D.N.A.)
I'm beautiful in my way
'Cause God makes no mistakes
I'm on the right track, baby
I was born this way
Don't hide yourself in regret
Just love yourself and you're set
I'm on the right track, baby
I was born this way
Oh there ain't no other way
Baby I was born this way
Baby I was born this way (born this way)
Oh there ain't no other way
Baby I was born this way
I'm on the right track, baby I was born this way
Don't be
(Don't be)
(Way) Church
Don't be a drag, just be a queen
Whether you're broke or evergreen
You're black, white, beige, chola descent
You're Lebanese, you're Orient
Whether life's disabilities
Left you outcast, bullied, or teased
Rejoice and love yourself today
'Cause baby you were born this way
No matter gay, straight, or bi
Lesbian, transgendered life
I'm on the right track baby
I was born to survive
No matter black, white or beige
Chola or orient made
I'm on the right track baby
I was born to be brave
I'm beautiful in my way
'Cause God makes no mistakes
I'm on the right track, baby I was born this way
Don't hide yourself in regret
Just love yourself and you're set
I'm on the right track, baby
I was born this way yeah
Oh there ain't no other way
Baby I was born this way
Baby I was born this way (born this way)
Oh there ain't no other way
Baby I was born this way
I'm on the right track, baby I was born this way
I was born this way hey
I was born this way hey
I'm on the right track baby
I was born this way hey
I was born this way hey
I was born this way hey
I'm on the right track baby
I was born this way hey
Same D.N.A. But born this way
Same D.N.A. But born this way

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Are these right triangles ?<br> Answer please ASAP

V125BC [204]

Answer: Yes.

Step-by-step explanation: Right triangles are 90° and with a square. This is a right triangle. Just remove the line that makes it a triangle, you'll see.

4 0

3 years ago

The product of 2√ 3 and 3√12 in simplified form is .

borishaifa [10]

Answer:

Step-by-step explanation:

Rewrite this as

(2)(3)(√3)(√12), or

6 * √36, or

6 * 6 = 36

5 0

3 years ago

Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are

Svetlanka [38]

Answer:

(a) Number of sets B given that

A⊆B⊆C: 2¹⁰. (That is: A is a subset of B, B is a subset of C. B might be equal to C)
A⊂B⊂C: 2¹⁰ - 2. (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

Let $x_1, x_2, \cdots, x_{20}$ denote the 20 elements of set X.

Let $x_1, x_2, \cdots, x_{10}$ denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain $x_1, x_2, \cdots, x_{10}$ .

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from $x_1, x_2, \cdots, x_{20}$ .

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves $2^{10} -2 = 1024 - 2 = 1022$ possibilities.

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's $2^{20} = 1048576$ possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only $2^{20} - 2^{10}$ possibilities left.

5 0

3 years ago

The world's population has grown at an average rate of 1.9 percent per year since 1945. There were approximately 4 billion peopl

kkurt [141]

Answer: $f(t) = 4000000000( 1 .019)^t$

Step-by-step explanation:

Here, According to the question, The population of the world is 4 billion (approx).

Again According to the question, The world's population has grown at an average rate of 1.9 percent per year since 1945.

Therefore, after 1975 the growth rate will remains same.

Thus, the population of the world after t years,

$f(t) = 4000000000( 1+\frac{1.9}{100} )^t$ (By the formula $A = P(1+\frac{r}{100})^t$ )

⇒ $f(t) = 4000000000( 1.019 )^t$

Where 1.019 is the growth rate and 4 billion is the initial population.

6 0

3 years ago

A graph of a quadratic function y = f(x) is shown below.

spin [16.1K]

We are given a graph of a quadratic function y = f(x) .

We need to find the solution set of the given graph of a quadratic function .

<em>Note: Solution of a function the values of x-coordinates, where graph cut the x-axis.</em>

For the shown graph, we can see that parabola in the graph doesn't cut the x-axis at any point.

It cuts only y-axis.

Because solution of a graph is only the values of x-coordinates, where graph cut the x-axis. Therefore, there would not by any solution of the quadratic function y = f(x).

<h3>So, the correct option is 2nd option :∅.</h3>

8 0

4 years ago

Read 2 more answers