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slavikrds [6]
3 years ago
6

Solve the equation (3x+2)(x-5)=0. Enter the solution with the highest value

Mathematics
2 answers:
vodka [1.7K]3 years ago
5 0

Answer:

5 is the solution with the greater value; -2/3 is the other solution.

Step-by-step explanation:

Set each factor of (3x+2)(x-5)=0 equal to zero and solve for x in each case:

3x+2 = 0 => 3x = -2 => x = -2/3

x-5 = 0 => x = 5


Brilliant_brown [7]3 years ago
4 0

Answer:

the answer for apex is 5

Step-by-step explanation:

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Marcus is shopping for pants. The available styles are boot cut (B), skinny (S), and relaxed fit (R). Make an organized list to
finlep [7]

Answer:

list in the explanation

Step-by-step explanation:

BOOT x2

SKINNY x2

RELAXED x2

BOOT, SKINNY

BOOT, RELAXED

SKINNY, BOOT

SKINNY, RELAXED

RELAXED, BOOT

RELAXED, SKINNY

6 0
3 years ago
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
What is the difference between 3/7 and 1/14?
Elena-2011 [213]
C. 5/15
First, change 3/7 to have the same denominator as 1/14.
3/7=6/14 because 7•2=14 (denominator) 3•2=6 (numerator)
Next, subtract 1/14 from 6/14.
6/14-1/14=5/14
3 0
2 years ago
???????????????????????
aleksandrvk [35]
The answer is 10w.

40 divided by 4 is 10. The X and Y cancel out, leaving 4W.
6 0
3 years ago
Someone please tell me the domain and range. Thank you.
Tanya [424]

one is (5) because Domain is left to right

and number two is (4) because range is up and down

4 0
3 years ago
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