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3 years ago

Add or Subtract x/x-6 + 3/x+7

1 answer:

3 0

${\frac{x}{x-6}+\frac{3}{x+7}=\frac{x(x+7)+3(x-6)}{(x-6)(x+7)}=\frac{x^2+7x+3x-18}{(x-6)(x+7)}=\frac{x^2+10x-18}{(x-6)(x+7)}}$

domain

$x\ne 6 \ , \ x\ne -7 \\\\ D: \ x \in \mathbb R - \{-7,6\}$

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According to Brad, consumers claim to prefer the brand-name products better than the generics, but they can't even tell which is

max2010maxim [7]

Answer:

a. There is not enough evidence to support the claim that the proportion that correctly identifies the chip is significantly smaller than 50%.

b. Test statistic z=-1.001

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that the proportion that correctly identifies the chip is significantly smaller than 50%.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.5\\\\H_a:\pi$

The significance level is 0.01.

The sample has a size n=199.

The sample proportion is p=0.462.

$p=X/n=92/199=0.462$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.5*0.5}{199}}\\\\\\ \sigma_p=\sqrt{0.001256}=0.035$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.462-0.5+0.5/199}{0.035}=\dfrac{-0.035}{0.035}=-1.001$

This test is a left-tailed test, so the P-value for this test is calculated as:

$\text{P-value}=P(z$

As the P-value (0.16) is greater than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the proportion that correctly identifies the chip is significantly smaller than 50%.

7 0

4 years ago

Help i dont know the formula for the triangle to find the answer its surface area n volume

777dan777 [17]

Answer:

#4=10.5

#5=48

Step-by-step explanation:

The formula for the triangle for area is 1/2 time base times hight

The forumale fot the triangle for volume is 1/2 time base times hight

So for number #4 it will be 1/2 x 3 x 7

and number #5, it will be 1/2 x 8 x 12

5 0

3 years ago

In which quadrants do solutions for the inequality y ≤ 2/7x +1 exist?

viktelen [127]

All four quadrants

<h2>Explanation:</h2>

We have the following inequality:

$y \leq \frac{2}{7}x+1$

So the first step we need to perform is to plot the line:

$y = \frac{2}{7}x+1$

$If \ x=0 \\ \\ y=\frac{2}{7}(0)+1 \\ \\ y=1 \\ \\ \\ If \ y=0: \\ \\ 0=\frac{2}{7}(x)+1 \\ \\ x=-\frac{7}{2}=-3.5$

So the line passes through the points:

$(0,1) \ and \ (-3.5,0)$

To find the shaded region, let us take a point, namely, the origin and test it in the inequality:

$y \leq \frac{2}{7}x+1 \\ \\ 0\leq \frac{2}{7}(0)+1 \\ \\ 0\leq 1 \ True!$

Since this is true, then the shaded region includes this point. This is shown below and <em>as you can see the solutions exist in all four quadrants.</em>

<h2>Learn more:</h2>

Inequalities: brainly.com/question/12890742

#LearnWithBrainly