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2 years ago

Please help will brainlest

Mathematics

2 answers:

Ahat [919]2 years ago

4 0

Answer:

1) 8zs² × 4z³s^5

= 32z⁴s^7

2) 5w^5 × 4w⁴

= 20w^9

3) 3r × 5r^5

= 15r^6

4) cz × 9c^5z²

= 9c^6z³

5) (1/r)⁴ × (1/r)^7 × (1/r)^6

= r^-4 × r ^ -7 × r^ -6

= r^ -17

6) 4h^6 × 2h³c²

= 8h^9c²

Hope this helps.

liubo4ka [24]2 years ago

3 0

Answer:

1. = 32z4s7 2.= 20w9 3.= 15r6 8.= 9c6z3 (i don't know 9 sorry) 10.= 8h9c2

Step-by-step explanation:

the numbers that come AFTER the letters are the powers.

You might be interested in

Can someone please explain how to do this?

wolverine [178]

Answer: 15,000

Step-by-step explanation:

When you subtract 75,000-60,000, you will get 15,000 and 15,000 is the Variance.

Hope this helps! Thanks for asking.

7 0

3 years ago

A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week

Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of individuals who work at home at least once per week = $\frac{41}{250}$ = 0.164

n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<em>99% confidence interval for p</em> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ , $0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ ]

= [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

7 0

2 years ago

You’re help Is greatly appreciated!! I will mark BRAINLIEST as well

Akimi4 [234]

Answer:

1. -4/7

2. 4/3

3. x^2 + 16x + 63

4. x^2 + 19x + 90

Step-by-step explanation:

1. (1, 8) and (8, 4)

slope = m = (8 - 4)/(1 - 8) = -4/7

2. (2, 4) and (5, 8)

slope = m = (8 - 4)/(5 - 2) = 4/3

3. (x + 9)(x + 7) =

= x^2 + 7x + 9x + 63

= x^2 + 16x + 63

4. (x + 10)(x + 9) =

= x^2 + 9x + 10x + 90

= x^2 + 19x + 90

6 0

3 years ago

a phone company offers two monthly charge, in Plan a, the customer pays a monthly fee of $40.10 and then an additional 4 cents p

Charra [1.4K]

Answer:

x > 1.7 minutes

The monthly telephone usage amounts so that plan A is not greater than plan B are all greater than 1.7 minutes.

Step-by-step explanation:

The two plans must be defined by the equation of the line y = mx + b, where

y = plan

m = slope or payment of additional cents per minute

x = time expressed in minutes

For Plan A, we have

y = 4x + 40.10 (Equation A)

While plan B is defined as

y = 7x + 35 (Equation B)

Plan A must be less than Plan B,

4x + 40.10 < 7x + 35

We put the “x” on the left side and the independent terms on the right side,

4x - 7x < 35 - 40.10

We add algebraically,

-3x < -5.10

We multiply the equation by -1 to eliminate the two “minus” signs, changing the inequality sign,

3x > 5.10

We isolate x,

x > 5.10 / 3

We solve, calculating the value of x,

x > 1.7 minutes

The monthly telephone usage amounts so that plan A is not greater than plan B are all greater than 1.7 minutes.

7 0

3 years ago

462.6017281 what is the nearest tenth

Westkost [7]

Answer:

462.60

Step-by-step explanation:

1-5 the #stays the same

6-10 goes to the next # up

7 0

3 years ago