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bazaltina [42]
2 years ago
7

Probability and statistics

Mathematics
1 answer:
Hatshy [7]2 years ago
3 0

Answer:

First: 4/10 aka 2/5

Second: 3/9 aka 1/3

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Factor the expression -10x^2-41x-21
BaLLatris [955]
-10x^2-41x-21= -(10x^2+41x+21) =-(10x^2+35x+6x+21)=\\\\=- [(10x^2+35x)+(6x+21 )]=- [5x(2x +7 )+3(2x+7 )]=-(2x+7)(5x+3)


5 0
2 years ago
Read 2 more answers
An investigator wants to assess whether the mean m = the weight of passengers flying on small planes exceeds the FAA guideline o
stira [4]

Answer:

H_{0}: \mu= 185 and H_{a}: \mu > 185

Step-by-step explanation:

The null hypothesis H_{0} states that a population parameter (such as the mean, the standard deviation, and so on) is equal to a hypothesized value. We can write the null hypothesis in the form H_{0}: parameter = value

In this context, the investigator's null hypothesis should be that the average total weight is no different than the reported value by the FAA. We can write it in this form H_{0}: \mu= 185.

The alternative hypothesis H_{a} states that a population parameter is smaller, greater, or different than the hypothesized value in the null hypothesis. We can write the alternative hypothesis in one of three forms

H_{a}: parameter > value\\H_{a}: parameter < value\\H_{a}: parameter \neq value

The investigator wants to know if the average weight of passengers flying on small planes exceeds the FAA guideline of the average total weight of 185 pounds. He should use H_{a}: \mu > 185 as his alternative hypothesis.

7 0
3 years ago
How much time does it take for a squirrel to run 134 meters at a speed of 12 meters per second?
aleksley [76]
11 2/3 seconds at a speed of 12 m/s
4 0
3 years ago
Read 2 more answers
The speed of a sparrow is x km/h in still air. When the
Semmy [17]

Answer:

x = 5m/s

Step-by-step explanation:

Distance flying out = 12 km  (headwind)

Distance flying back = 12 km (tailwind)

total distance = 12 + 12 =24 km

wind speed = 1km/h

speed going out (with headwind) = (x - 1) km/h

speed coming back (with tailwind) = (x + 1) km/h

Time taken to go out = distance going out / speed going out

= 12 / (x-1)

Time taken to come back = distance coming back / speed coming back

= 12 / (x+1)

total time = time taken to go out + time taken to come back

5 =[ 12/(x-1) ] + [ 12/(x-1)]

expanding this, we will get

5x² - 24x - 5 = 0

solving quadratic equation, we will get

x = -1/5 (impossible because speed cannot be negative)

or

x = 5 (answer)

4 0
3 years ago
X squared=yw-3 make x the subject
KengaRu [80]
X²=yw-3
sqrt both sides
x=\sqrt{yw-3}
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3 years ago
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