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AleksAgata [21]
3 years ago
11

A 12 foot ladder is placed 5 feet from the base of the building. About how high does the ladder reach?

Mathematics
1 answer:
Mariulka [41]3 years ago
8 0

Answer:

7 foot

Step-by-step explanation:

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Given:

D=165 feet and the frequency of the motion is 1.6 revolutions per minute.

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The radius is half of the diameter.

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As we know: \omega=\frac{2\pi}{T}

Substitute the value of T in the above formula.

\omega=\frac{2\pi}{\frac{1}{1.6}}\\\omega=3.2\pi

If the center of the wheel is at the origin then for t=0 the rest position is -a.

This can be written as:

h(t)=-a\cos(\omega t)\\h(t)=-82.5cos(32.\pi t)

The actual height of the rider from the ground is:

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The required equation is h(t)=97.5-82.5\cos(3.2\pi t).

3 0
3 years ago
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Norma-Jean [14]

Answer:

1/216

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Simplify to create an equivalent expression. 8−4(−x+5)
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As you already know, in order to find the equivalent expression to our already given one, we have to simplify it first :)

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Add like terms.

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Get rid of parenthesis.

4x - 12

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mafiozo [28]

Answer:

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Step-by-step explanation:

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