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Pie
3 years ago
8

Yousef competes in the long jump and gets three attempts. The distances jumped are 5.6 meters, 5.62 meters, and 5.59 meters. Whi

ch shows these distances ordered from least to greatest?
Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0

Answer:

5. 59 meters, 5.6 meters, 5.62 meters.

Step-by-step explanation:

The distances jumped are 5.6 meters, 5.62 meters, and 5.59 meters.

Each of these numbers have 5 before decimal point, so in order to compare these numbers, take a look at the first digit after decimal point: 6, 6 and 5. Since 5 is less than 6, number 5.59 is the smallest one. Take a look at the second digit after point in first two numbers. They are 0 and 2. Since 0 is less than 2, then number 5.6 is smaller than 5.62,

so the correct order is

5. 59 meters, 5.6 meters, 5.62 meters.

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3 years ago
Which situation could this expression represent?
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The answer is c because it’s 9+6 and then u divide it it just makes more since
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3 years ago
Read 2 more answers
Enter an inequality that represents the graph in the box.
Yuliya22 [10]

Find 2 points on the line:

We will use (2,2) and (0,-6)

Find the slope of the line which is the change in Y over the change in X:

(-6-2) / (0-2) = -8/-2 = 4

The slope = 4

Find the Y intercept:

y = 4x+b

use y1 for y and x1 for x

2 = 4(2) +b

2 = 8 +b

Subtract 8 from both side:

b = -6

Now you have the slope (4) and Y intercept (-6)

The equation of the line becomes y = 4X-6

The line is solid and the shaded portion of the graph is to the left of the line and it is a positive slope so the inequality would become

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7 0
3 years ago
22. Determine the value of c so that the line
tiny-mole [99]

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints  D(c, -7) and E(5, -3).

Using slope formula: Slope=\frac{y_2-y_1}{x_2-x_1} we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}

We have:

x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \

Putting values and finding c

\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2

So, If the lines BC and DE are parallel, the value of c is c=-2

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4 years ago
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Answer:

A would be the correct answer. I took this



Step-by-step explanation:

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3 years ago
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