X intercept- 3.5
y intercept- 2.5
![y=\frac{1}{2}x+3 \parallel y=mx+b](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7Dx%2B3%20%5Cparallel%20y%3Dmx%2Bb)
Two lines are parallel when their slopes are the same.
<h3>Given ↓</h3>
- Two points that a line goes through
<h3>To Find ↓</h3>
<h3>Calculations ↓</h3>
When we have two points that a line passes through and asked to determine the slope of the line, the slope formula is going to come in handy.
This is the formula :
![\boxed{\\\begin{minipage}{3cm}slope~formula~: \\ $\displaystyle\frac{y2-y1}{x2-x1}$ \\ \end{minipage}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5C%5C%5Cbegin%7Bminipage%7D%7B3cm%7Dslope~formula~%3A%20%5C%5C%20%24%5Cdisplaystyle%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%24%20%5C%5C%20%5Cend%7Bminipage%7D%7D)
y2 and y1 are y-coordinates, and x2 and x1 are x coordinates
Plug in the values :
![\boxed{\\\begin{minipage}{3cm}$\displaystyle\frac{0-(-7)}{7-0} $\end{minipage}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5C%5C%5Cbegin%7Bminipage%7D%7B3cm%7D%24%5Cdisplaystyle%5Cfrac%7B0-%28-7%29%7D%7B7-0%7D%20%24%5Cend%7Bminipage%7D%7D)
![\boxed{\\\begin{minipage}{3cm}$\displaystyle\frac{0+7}{7} \end{minipage}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5C%5C%5Cbegin%7Bminipage%7D%7B3cm%7D%24%5Cdisplaystyle%5Cfrac%7B0%2B7%7D%7B7%7D%20%5Cend%7Bminipage%7D%7D)
Which simplifies to
, or 1
<h3>Slope ↓</h3>
1 (Option D.)
hope helpful ~
Answer:
27 degrees
Step-by-step explanation:
First, we can draw this out. Since the altitude is 8000, we can make that the height, and it goes 16000 feet through the air, that can be the length. I have drawn this out, as shown in the image. Note that when drawing, because the airplane is going up and forward, that path should represent the hypotenuse. The angle of elevation is the angle connecting the length and the path, as shown by the angle x in the picture.
We know than tan(x) = opposite/adjacent, so tan(x) here = 8000/16000 = 1/2. Then, arctan(1/2) =x = 27 degrees