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densk [106]
3 years ago
15

Express x-1y-2/z-3 with positive exponents.

Mathematics
2 answers:
Marysya12 [62]3 years ago
8 0

x^-1y^-2/z^-3

=z^3 / (xy^2)

Kay [80]3 years ago
3 0
1/y^-2 = y^2 

<span>Hopefully this also can help :)</span>
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Is 4:7 8:15 16:28 2:3 20:35 eqivalent to each other
igor_vitrenko [27]

4:7 16:28 20:35


Hope this helps. :)

5 0
2 years ago
Customers arrive at a bank at a rate of 12/hour. It takes the clerk on average 4 minutes to help each customer. a. What is the a
-Dominant- [34]

Answer:

Step-by-step explanation:12 customers per hour..

4minutes per customer..

Time customers must wait= 12customers ×4minutes =48 minutes.. The clerk use 48minutes to attend to 12customers in one hour leaving him with 12spare minutes.

(B)since the clerk has 12 minute to spare it means each customer have a minute to wait before getting attention..

(C)number of customers waiting =12/2=6customers...

4 0
3 years ago
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
2 years ago
Can someone tell me the answer please?
vovikov84 [41]
6.241 I think that's right
4 0
3 years ago
If 600 cm2 of material is available to make a box with a square base and a closed top, find the maximum volume of the box in cub
dangina [55]
Area of the box:
A = 2 a² + 4 a h = 600 cm²
h = a ( the box is a cube )
A = 6 a² = 600 cm²
a² = 100
a = 10 cm
V = a³ = 10³ = 1000 cm³
4 0
3 years ago
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