To find the mean, you add up the numbers and divide by
how many numbers there are.
So if the mean of 'A' and 'B' is 40, then A + B = 80 .
And if the mean of 'B' and 'C' is 35 then B + C = 70.
==========================================
You said that (A + B) + C = 100 .
From something else that you said, I noticed that A + B = 80 .
So I can write (80) + C = 100
Subtract 80 from each side: C = 20
==========================================
I also noticed, from what you said, that B + C = 70 .
So I can write B + 20 = 70
Subtract 20 from each side: B = 50
==========================================
Now I know that C = 20 and B = 50.
Finally, you said that A + B + C = 100 ,
So I can write A + 50 + 20 = 100
Combine like terms on the left: A + 70 = 100
Subtract 70 from each side: A = 30
==========================================
<em> A = 30</em>
<em> B = 50</em>
<em> C = 20</em>
Answer:
9
Step-by-step explanation:
You know that the the center line is equal to half the sum of the legs, because it is the midline. You add the legs together (7x+13) and (5x+7), and you get 12x+20. Divide that by 2 and you get 6x + 10. The midline is 8x-8, so you set up an equation, and get 6x+10 = 8x-8. That simplifies to 18=2x. Divide both sides by 2 and you get x = 9
Answer:
B
Step-by-step explanation:
<u><em>I think this is your full question and hope it is correct. </em></u>
<em>Which system of equations could be graphed to solve the equation below?
</em>
<em>log(2x+1)=3x-2
</em>
<em>A. y1=3x, y2=2x
</em>
<em>B. y1=log(2x+1), y2=3x-2
</em>
<em>C. y1=log2x+1, y2=3x-2
</em>
<em>D. y1=log(2x+1+2), y2=3x</em>
My answer:
We know that: log(2x+1)=3x-2 and they are a equation of log and linear so we need to make system of equation.
The left side is: 
=> 
The right side is : 
The system of equations are:
Now we have two new function with x and y.
<em />
26 because they have to pay for it in a deminsion
