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Anit [1.1K]
2 years ago
7

Rewrite each equation to solve for m.

Mathematics
1 answer:
Damm [24]2 years ago
7 0

Answer:

1. M = 7-5n

2. M = 5n - 8 / 4

3. M = - 8n - 1 / 3

4. M = - -5n-13/3

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3/4 of x if x= 15/28<br> PLS HELP!!!!!!!
vfiekz [6]

Answer:

5/7

Step-by-step explanation:

first of mean to divide

so it really saying x ÷ 3/4 and x = 15/28

15/28 ÷ 3/4 but you cant divide fractions

so we use copy dote flip

copy 15/28

dote ×

flip 4/3

15/28 × 4/3

then cross simplafiy so 4 can go into 28, 7 rimes. and 3 can go into 15, 5 times

5/7

6 0
3 years ago
Read 2 more answers
Given f(x) = √(x-3) , what is the positive value of f(12)?
Shalnov [3]

Answer:

3

Step-by-step explanation:

Given

f(x) = \sqrt{(x-3)} , then

f(12) = \sqrt{12-3} = \sqrt{9} = ± 3

There are 2 values 3 and - 3

The positive value of f(12) is + 3

6 0
3 years ago
Derek was 4 years 2 months old when he joined school. Today he is 11 years 1 month old. For how long has he been in school?
lora16 [44]

Answer:

hi

Step-by-step explanation:

first of all,we should do this:

1 year is 12 month

amd 4 year is 48 month(12×4)

then we must add 2 months (wich is given) to 48

He was 50 months old when he started school

and we should find how old is he now

11 ×12=132months

132+1=133months

133-50=83 ( he has been 83 months in school)

let's turn it to years 6 years 11 months

( for finding years you should divide 83 to 12)

hope it helps

6 0
2 years ago
Solve with elimination
Fittoniya [83]
I'm pretty sure this is correct

4 0
3 years ago
What is a relation and what makes it different from a function? How can you determine the domain and range of a function?
Misha Larkins [42]

Answer:

Note that both relations and functions have domains and ranges. The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.

6 0
3 years ago
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