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2 years ago

Rewrite each equation to solve for m.

Mathematics

1 answer:

Damm [24]2 years ago

7 0

Answer:

1. M = 7-5n

2. M = 5n - 8 / 4

3. M = - 8n - 1 / 3

4. M = - -5n-13/3

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Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx$

Where m =slope

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$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$m2=-\dfrac{3}{2}$

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$m2=-\dfrac{3}{2}$

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$(y-7)=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

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3 years ago