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o-na [289]
3 years ago
15

Who much time would it take for a train accelerating at 21.5 m/s2 to go from

Mathematics
2 answers:
Nina [5.8K]3 years ago
8 0

Answer:

Step-by-step explanation:

v=u+at

38.9=13.2+21.5 t

21.5 t=38.9-13.2

21.5 t=25.7

t=25.7/21.5≈1.195 s

BaLLatris [955]3 years ago
5 0

Answer:

To find the time taken, we use the equation:

v

=Then to find the time taken, we use the equation:

v = u + at

where:

v is the final velocity of the train

u is the initial velocity of the train

a is the train's acceleration

t is the time taken

So, we get:

t = (v-u)/a

t = (38.9 - 13.2)/21.5

t = 25.7/21.5

t = 1.19 seconds

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The formula for the surface area, S, of a cylinder, is S = 2tr2 + 2trh, where h is
kykrilka [37]

Answer:

H = 2        S = 50    A = 50.2

Step-by-step explanation:

A=2πrh+2πr2

S = 2tr2 + 2trh

S = 2 (t x r) + (h x 2t) x r   Try out ^2 for Radius

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S = 6 x 4 + 6 x 2 x h  Balance out...

S= 24 + 12 x 2    Find h = 2

S = 36 + 24

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A = 50. 2

R = 2

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Checker

Area = 6.28318530718 x 4 + 6.28318530718  x 2 x 2 = 50.27sq2

7 0
3 years ago
In your own words, explain the steps you would need to take to find a slope from data in a table.
OverLord2011 [107]

Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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3 years ago
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