Two planes intersect at a Line.
It’s d, 1 - t
t + 3 - 2 - 2t
we can rearrange it as
t - 2t + 3 - 2
-t + 1 is the same as 1 - t
2sinxcosx - sin(2x)cos(2x) = 0
<span>Part I </span>
<span>The double angle identity for sine states that sin(2x) = 2sinxcosx </span>
<span>Thus we get: </span>
<span>sin(2x) - sin(2x)cos(2x) = 0 </span>
<span>Part II </span>
<span>sin(2x)(1 - cos(2x)) = 0 </span>
<span>Part III </span>
<span>Either sin(2x) = 0 or </span>
<span>1 - cos(2x) = 0 </span>
<span>=> cos(2x) = 1 </span>
<span>For sin(2x) = 0, this is true for </span>
<span>2x = n(pi) where n = 0, 1, 2, .... </span>
<span>x = n(pi/2) </span>
<span>For cos(2x) = 1, this is true for </span>
<span>2x = n(pi) where n = 0, 2, 4, .... </span>
<span>x = n(pi/2)
</span>
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Answer:
x = 10/3
, y = 0
Step-by-step explanation:
Solve the following system:
{4.5 x - 2 y = 15
3 x - y = 10
In the first equation, look to solve for x:
{4.5 x - 2 y = 15
3 x - y = 10
4.5 x - 2 y = (9 x)/2 - 2 y:
(9 x)/2 - 2 y = 15
Add 2 y to both sides:
{(9 x)/2 = 2 y + 15
3 x - y = 10
Multiply both sides by 2/9:
{x = (4 y)/9 + 10/3
3 x - y = 10
Substitute x = (4 y)/9 + 10/3 into the second equation:
{x = (4 y)/9 + 10/3
3 ((4 y)/9 + 10/3) - y = 10
3 ((4 y)/9 + 10/3) - y = ((4 y)/3 + 10) - y = y/3 + 10:
{x = (4 y)/9 + 10/3
y/3 + 10 = 10
In the second equation, look to solve for y:
{x = (4 y)/9 + 10/3
y/3 + 10 = 10
Subtract 10 from both sides:
{x = (4 y)/9 + 10/3
y/3 = 0
Multiply both sides by 3:
{x = (4 y)/9 + 10/3
y = 0
Substitute y = 0 into the first equation:
Answer: {x = 10/3
, y = 0
