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1 year ago

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SOVA2 [1]1 year ago

8 0

Here is the answer hope this helps

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Measurement maths!!<br> If good with area please help

Gennadij [26K]

Answer:

a. 15/2 or 7.5 sqcm

b. 20 sqcm

Step-by-step explanation:

Area of a triangle is (base × height)/2.

A = (5×3)/2

A = 15/2 = 7.5cm^2

The area of a parallelogram is just base × height, but yoy have to choose wisely what is the base and height. These two measurements must be perpendicular. So the 4 and 5 are perpendicular. We won't use the measurement 6cm at all.

Area = 4×5

Area = 20 sqcm

4 0

1 year ago

Factor completely 5x^2 + 20x

murzikaleks [220]

Answer: 5x(x + 4)

hope i helped

7 0

2 years ago

Read 2 more answers

PLEASE HELP!!!What are good 3 examples of Geography?WILL GIVE BRAIN!!!

zvonat [6]

Answer:

The three main types of geography are physical, environmental and human geography. There are other sub-branches of geography such as political geography, historical geography and religious geography.

Physical geography deals with the study of Earth and its structure. The landforms, continents, oceans and tectonic movements are a part of physical geography. The formation of rocks, weathering, forces of erosion, winds, ocean currents and rivers are all studied as a part of physical geography. Environment geography deals specifically with the study of the interaction of plants and animals with Earth. Human geography focuses on how human societies flourish with the help of natural resources. It deals with the study of the evolution of cultures and religious beliefs. Economic, cultural and political geography are sub-branches of human geography.

Step-by-step explanation:

plz mark as brainliest

8 0

2 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

2 years ago

Will give brainliest

posledela

Answer:

8

Step-by-step explanation:

hope it will help good luck

7 0

3 years ago