I think u add not sure though
Answer:
3 dogs and 2 cats.
Step-by-step explanation:
In this case we can solve it using a 2x2 system of equations, like this:
let x: number of cats
let y: number of dogs
So:
42.5 * x + 64 * y = 277
35.5 * x + 50.5 * y = 222.5 => x = (222.5 - 50.5 * y) /35.5
Replacing, we are left with that:
42.5 * (222.5 - 50.5 * y) /35.5 + 64 * y = 277
266.37- 60.45 * y + 64 * y = 277
64 * y - 60.45 * y = 277 - 266.37
3.55 * y = 10.63
y = 10.63 / 3.55
y = 2.99, about 3
Now to calculate x:
x = (222.5 - 50.5 * 3) /35.5
x = 2
Which means that it has a total of 3 dogs and 2 cats.
Y=2x+320
x being the number of years and 320 being the initial population of mice
<span>87 less than the quotient of an unknown number and 43 is -75
Converting that to mathematical equation:
87 - (x / 43) = -75
Evaluating the equation, we can the value of x.
87 - (x/43) = -75
-x/43 = -75 - 87
-x/43 = -162
-x = -6966
x = 6966</span>
10% of 320 = 32
So 9.8% of 320 should be some number between 31 and 32
