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Answer:
Step-by-step explanation:
Volume of first container = 48 cm³
πr²h = 48 cm³
Second container:
height = (2/3)h
Volume of second container=
![=\pi *r^{2}*(\frac{2}{3}*h)\\\\=\frac{2}{3}*\pi *r^{2}*h\\\\](https://tex.z-dn.net/?f=%3D%5Cpi%20%2Ar%5E%7B2%7D%2A%28%5Cfrac%7B2%7D%7B3%7D%2Ah%29%5C%5C%5C%5C%3D%5Cfrac%7B2%7D%7B3%7D%2A%5Cpi%20%2Ar%5E%7B2%7D%2Ah%5C%5C%5C%5C)
=(2/3)* first container's volume {πr²h = 48 cm³}
![=\frac{2}{3}*48\\\\=2*16\\\\](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B3%7D%2A48%5C%5C%5C%5C%3D2%2A16%5C%5C%5C%5C)
= 32 cm³
The answer is 540 m2 hope this helps
The answer to this question would be x=a2y2
Answer:
x = 4
Step-by-step explanation:
An exterior angle of a triangle is equal to the sum of the remote interior angles.
18x +5 = (46) +(-1 +8x)
10x = 40 . . . . . . . . . . . . . subtract (5+8x) from both sides, simplify
x = 4 . . . . . . divide by 10
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<em>Additional comment</em>
The exterior angle is (18)(4) +5 = 77°. The marked unknown interior angle is -1+(8)(4) = 31°. The sum of the two remote interior angles is 46°+31° = 77°. The unmarked interior angle is 180°-77° = 103°.