Answer:
B
Step-by-step explanation:
Answer:
<em>0 $20 bills and 10 $5 bills</em>
<em>1 $20 bills and 6 $5 bills</em>
<em>2 $20 bills and 2 $5 bills</em>
Step-by-step explanation:
<u>Equations</u>
Let's set:
x=number of $5 bills
y=number of $20 bills
The total amount Sara has is given by
5x+20y
And we know it's equal to $50, thus:
5x+20y=50
Dividing by 5
x+4y=10
We would need another condition to solve for x and y, but we can determine some combinations that solve the problem.
Solving for x:
x=10-4y
Since both x and y are integers and cannot be negative:
10-4y≥0
Swapping sides:
4y≤10
Dividing by 4:
y≤2.5
Thus, y can only have the values {0,1,2}
For y=0
x=10-4*0=10
x=10
For y=1
x=10-4*1=6
x=6
For y=2
x=10-4*2=2
x=2
Thus, the possible combinations are:
0 $20 bills and 10 $5 bills
1 $20 bills and 6 $5 bills
2 $20 bills and 2 $5 bills
Okay so for this one, we have to isolate our X.Lets start by moving the negative 5 on the other side of the equal sign. Remember to not mix a number that is with an X with a normal number (in this case it would be the -3x and the -5). So in putting our -5 on the other sign it becomes positive. Here’s what we have: x^2-3x=5. x^2 is the same thing as 2x.So now you have to minus 3x off of your 2x. This gives us -1x, but can just be put as -x. So now we have -x=5. You’re answer could either be 5 or -5 if you decided to divide it by -1 seeing as your -x is technically -1.
For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)
For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600
Sum of first 120 positive integers = s + s + 3600 = 2s + 3600
Answer:
Mean
Step-by-step explanation:
Since 360 is such a greater amount of time than the previous ones, it will greatly affect the mean.
