1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vovikov84 [41]
3 years ago
8

Write the inequality shown by the graph with the boundary line. y =?

Mathematics
2 answers:
Vinvika [58]3 years ago
6 0
Y> 4x+1
Your line is dotted meaning your function will not be equal to and the shaded section is going upward meaning your solutions will all be grader then the expression.
ElenaW [278]3 years ago
5 0
Y > 4x +1
Because the graph is shaded above with a dotted line.
You might be interested in
Write 4/5 with denominator 15
emmasim [6.3K]

Answer:

12 / 15

Step-by-step explanation:

4/5 = x /15

15 / 5 = 3

So multiply both numerator and denominator by 3

4/5 * 3/3 = 12 / 15

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

6 0
3 years ago
Read 2 more answers
What is the interval in which both f(x) and g(x) are positive?
padilas [110]

The positive interval of a function is when the function has positive values.

<em>The interval in which both f(x) and g(x) are positive is </em>(3,\infty)<em />

<em />

<em />

From the given graphs of g(x), we have the following observations.

  • <em>The graph of f(x) crosses the x-axis at </em>x =3<em />
  • <em>The graph of g(x) also crosses the x-axis at </em>x =3<em>.</em>

<em />

<em />

This means that:

<em />(x,y)= (3,0)<em> --- for both functions</em>

But when x increases, the value of y becomes positive,

<em>So, the positive interval of f(x) and g(x) is </em>(3,\infty)<em />

Read more about positive intervals at:

brainly.com/question/17238753

5 0
3 years ago
Write 2.1 as a mixed number show your work
Harman [31]

Answer:

2 1/10

Step-by-step explanation:

convert the decimal number to a fraction by placing the decimal number over a power of ten. since there is 1 number to the right of the decimal point, place the decimal number over 10^1 (10). next, add the whole number to the left of the decimal.

hope this helps

5 0
3 years ago
What is the simplest form of ^4 sqrt 81x^8y^5
lara31 [8.8K]

ANSWER

3 {x}^{2} y \sqrt[4]{y}

EXPLANATION

We want to simplify:

\sqrt[4]{81 {x}^{8} {y}^{5}  }

We can split the radical sign to obtain:

\sqrt[4]{81}  \times  \sqrt[4]{ {x}^{8} }  \times  \sqrt[4]{ {y}^{5} }

Or

\sqrt[4]{81}  \times  \sqrt[4]{ {x}^{8} }  \times  \sqrt[4]{ {y}^{4}  \times y}

\sqrt[4]{81}  \times  \sqrt[4]{ {x}^{8} }  \times  \sqrt[4]{ {y}^{4}}  \times  \sqrt[4]{y}

\sqrt[4]{ {3}^{4} }  \times  \sqrt[4]{ {x}^{8} }  \times  \sqrt[4]{ {y}^{4}}  \times  \sqrt[4]{y}

Recall that:

\sqrt[n]{ {a}^{m} }  =  {a}^{ \frac{m}{n} }

{3}^{4 \times  \frac{1}{4} }  \times  {x}^{8 \times  \frac{1}{4}  }  \times  {y}^{4 \times  \frac{1}{4} }\times  \sqrt[4]{y}

3 {x}^{2} y \sqrt[4]{y}

6 0
4 years ago
Read 2 more answers
A tree is 15 meters tall. A seedling next to it is 7 centimeters tall. What is the ratio of the height of the seedling to the he
tiny-mole [99]

Answer:

7/15

Step-by-step explanation:

it right i think if not srry :)

4 0
3 years ago
Other questions:
  • How many more dollars does she need
    6·1 answer
  • Help please help me please
    14·2 answers
  • There are 9 girls and 11 boys in a class, and two students will be chosen one after another. Find the probability that both are
    11·1 answer
  • Which is the last sentence of the proof?
    6·2 answers
  • What professional football team is the square of a prime number
    8·2 answers
  • Please help me with this thankyou​
    12·1 answer
  • Help me please LOL BAKANAJJAJAJANAJAHAHAHAHHAHA
    9·1 answer
  • Find the lengths of HJ
    11·1 answer
  • Find the simple interest and the total amount after three years.
    12·1 answer
  • Solve for x on number 13
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!