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3 years ago

Find the measure of YVZ

Mathematics

1 answer:

Arisa [49]3 years ago

5 0

Answer:

x 100

Step-by-step explanation:

because of the yvz angle its equals 100-12

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How many cents is equal $¼

Hitman42 [59]

Answer:

25 Cents

Step-by-step explanation:

1 / 4 = 0.25 = 25 cents

3 0

3 years ago

What is the inerquartile of the data set [40,48,62,40,25,50,20 30

Zanzabum

You just find the quartiles which are 62 and 50 the mines them which equals 12.

5 0

4 years ago

Read 2 more answers

Carlos takes classes at both Westside Community College and Pinewood Community College. At Westside, class fees are $ 98 per cre

Sholpan [36]

Answer:

x + y = 13

98x + 115y = z

Step-by-step explanation:

Let x represent the time spent taking class in Westside community college

Let y represent the time spent taking class in Pinewood community college

Let z represent the combined total amount paid for the class fees.

The total combined time for the two school is given as:

x + y = 13.

For the combined total amount; we multiply the price for each school with the time spent on the school and sum them together.

Westside: $98 * x = 98x$

Pinewood: $115 * y = 115y$

The combined total amount represented as z is given as:

z = 98x + 115y

7 0

4 years ago

Calculate and simplify:<br><br> 18/20 + 4/8 =

Vladimir [108]

Common denominator = 40

36/40 + 20/40 = 56/40

Reduce and simplify=

7/5, which is 1 and 2/5

Hope that helps

8 0

3 years ago

Read 2 more answers

Suppose that the terminal side of angle alphaα lies in Quadrant I and the terminal side of angle betaβ lies in Quadrant IV. If s

melamori03 [73]

Solution :

It is given that :

$\alpha$ lies in the first quadrant.

And $\beta$ lies in the fourth quadrant.

Since, $\sin \alpha = \frac{5}{13}$ and $\cos \beta = \frac{6}{\sqrt{85}}$ (given)

$\sin \alpha = \frac{5}{13}$

$\cos \alpha = \sqrt{1-\sin^2 \alpha}$

$\cos \alpha = \frac{12}{13}$

Similarly $\cos \beta = \frac{6}{\sqrt{85}}$

$\sin \beta = \sqrt{1-\cos^2 \beta}$

$\sin \beta = \sqrt{1-\frac{36}{85}}$

$-\frac{7}{\sqrt{85}}$ (IVth quadrant)

Therefore,

$\cos (\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta$

$=\frac{12}{13}\times \frac{6}{\sqrt{85}}-\frac{5}{13}\times \frac{-7}{\sqrt{85}}$

$= \frac{107}{13 \sqrt{85}}$

6 0

3 years ago