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2 years ago

Help! Expressions and equations

Mathematics

1 answer:

Dovator [93]2 years ago

5 0

Answer:

1. 16−6=10

2. 4⋅2+1

3. x÷25

4. y+8=40

Explanation:

This is an equation—two expressions are connected with an .This is an expression—no equal sign. This is an expression—no equal sign. This is an equation—two expressions are connected with an equal sign.

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As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur

Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math. It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

$y=Ce^{kt}$

Filling in our formula with the 2 conditions we are given:

$65=Ce^{10k}$ and $85=Ce^{15k}$

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k. If

$65=Ce^{10k}$ then

$\frac{65}{e^{10k}}=C$ which, by exponential rules is the same as

$C=65e^{-10k}$

Since that value of C is the same as the value of C in the other equation, we sub it in:

$85=65e^{-10k}(e^{15k})$

Divide both sides by 65 and use the rules of exponents again to get

$\frac{85}{65}=e^{-10k+15k}$ which simplifies down to

$\frac{85}{65}=e^{5k}$

Take the natural log of both sides to get

$ln(\frac{85}{65})=5k$

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

$65=Ce^{10(.0536527973)}$

which simplifies down to

$65=Ce^{.536527973}$

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

$y=38.01038064e^{(.0536527973)(23)}$ which simplifies a bit to

$y=38.01038064e^{1.234014338}$

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0

2 years ago

How do I solve this please? Can SOMEONE please help me this and the ones Iposted on my page.

vagabundo [1.1K]

Answer: $\dfrac{15}{64}$

Step-by-step explanation:

Given

Inside radius of figure $r_1=\frac{14}{2}=7\ ft$

Outside radius of figure $r_2=\frac{16}{2}=8\ ft$

Area of outside region is $A_1=\pi (8^2)$

Area of inside region $A_2=\pi (7)^2$

Area of shaded region $A_1-A_2$

Probability that point lies inside the shaded region is

$\Rightarrow P=\dfrac{A_1-A_2}{A_1}\\\\\Rightarrow P=\dfrac{\pi (8^2-7^2)}{\pi 8^2}\\\\\Rightarrow P=\dfrac{64-49}{64}\\\\\Rightarrow P=\dfrac{15}{64}$