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galben [10]
3 years ago
10

The function g(x) is defined as g(x) = 6x2 + 23x – 4. When does g(x) = 0? x = –6 or x = StartFraction 1 Over 4 EndFraction x = –

4 or x = StartFraction 1 Over 6 EndFraction x = StartFraction negative 1 Over 4 EndFraction or x = 6 x = StartFraction negative 1 Over 6 EndFraction or x = 4
Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0

Answer:

x = - 4 or x = \frac{1}{6}

Step-by-step explanation:

The function g(x) is defined as g(x) = 6x² + 23x – 4.

Now, we have to calculate x for f(x) = 0

So, 6x² + 23x - 4 = 0

⇒ 6x² + 24x - x - 4 = 0

⇒ (x + 4)(6x - 1) = 0

⇒ x = - 4 or x = \frac{1}{6}

Therefore, the second option is correct. (Answer)

NeTakaya3 years ago
3 0

Answer:

The answer is b.

Step-by-step explanation:

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For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?
Arlecino [84]

Answer:

For c=\frac{1}{7} the function f(x) is continuous on (-\infty,\infty).

Step-by-step explanation:

We have the following function

f(x) = \left\{        \begin{array}{ll}            cx^2+5x & \quad x

For the function f(x) to be continuous on (-\infty,\infty) it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x),

which holds if and only if

c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6

namely if c=\frac{1}{7}.

6 0
3 years ago
Another type of subtraction equation is 16-b=7. Explain how you would sole this equation then solve it.
sladkih [1.3K]

Answer: B = 9


Step-by-step explanation:


16-b=7

Rearrange so we can subtract 16 by 7

16 - 7 = 9


Substituting 9 for b and making sure it's correct.

16 - 9 = 7


4 0
4 years ago
Read 2 more answers
A bag contains 5 red marbles, 7 blue marbles and 4 green marbles if two marbles are drawn out of the bag what is the probability
Ann [662]

Answer:

0.083 probability that both are red

Step-by-step explanation:

total marbles = 5  + 7 + 4 = 16

Two marbles drawn out.

Find P(red, and red) =  (5/16) * (4/15) = 1/(3*4) = 1/12 = 0.08333

8 0
3 years ago
What is the horizontal asymptote of f (x) =StartFraction negative 2 x Over x + 1 EndFraction? y = –2 y = –1 y = 0 y = 1
miv72 [106K]

Answer:

  y = -2

Step-by-step explanation:

Any asymptotes of a rational function will be described by the quotient of the numerator and denominator (excluding any remainder).

  f(x)=\dfrac{-2x}{x+1}=-2+\dfrac{2}{x+1}

The horizontal asymptote is ...

  y = -2

8 0
3 years ago
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Simplify 6x.h.x.2xm. please
mixas84 [53]

7x . h . 2xm


You can put together 6x and x

but since h, and 2xm arent alike terms, you cant combine


6 0
3 years ago
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