Tanα=5/12
α=arctan(5/12)°
α≈22.62° (to nearest hundredth of a degree)
Divide the number of fast balls by the total number of pitches:
240 / 384 = 0.625
Answer:
The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.
Step-by-step explanation:
A confidence interval has the following format.

In which
is the mean of the sample and M is the margin of error.
In this problem, we have that:



The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.
I’m pretty sure it’s the second option.
Answer:
<u>-10x+25</u>
<em>Step-by-step explanation:</em>
−5(2x−5)
=(−5)(2x+−5)
=(−5)(2x)+(−5)(−5)
<u>=−10x+25</u>