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3 years ago

8

Arun takes 17 1/3 minutes to run around the school ground . Sanjay takes 12 1/5 to do the same . Who takes lesser time and by wh

at fraction??

1 answer:

Fed [463]3 years ago

7 0

Sanjay would be faster

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2 years ago

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valentina_108 [34]

Answer:

Step-by-step explanation:

Consider curl $(fF)$ where $f$ is a scalar function and F is a vector function

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$curl(fF)=i(\frac{\partial}{\partial y}(fF_{3})-\frac{\partial}{\partial z}(fF_{2}))-j(\frac{\partial}{\partial x}(fF_{3})-\frac{\partial}{\partial z}(fF_{1}))+k(\frac{\partial}{\partial x}(fF_{2})-\frac{\partial}{\partial y}(fF_{1}))$

$=i(\frac{\partial}{\partial y}(F_{3})+\frac{\partial}{\partial y}(f)-\frac{\partial}{\partial z}(F_{2})-\frac{\partial}{\partial z}(f))-j(\frac{\partial}{\partial x}(F_{3})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial z}(F_{1})-\frac{\partial}{\partial z}(f))+k(\frac{\partial}{\partial x}(F_{2})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial y}(F_{1})-\frac{\partial}{\partial y}(f))$

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2 years ago

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Zina [86]

The answer to this question is b

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3 years ago

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Diano4ka-milaya [45]

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Yes, I believe that is correct. I may be wrong.

Step-by-step explanation:

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2 years ago

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3 years ago