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3 years ago

F f(x) = 6x – 4, what is f(x) when x = 8?

Mathematics

2 answers:

dlinn [17]3 years ago

7 0

Replace x in the equation with 8 and solve:

f(x) = 6x - 4

x = 8

f(x) = 6(8) - 4

f(x) = 48 - 4

F(x) = 44

stellarik [79]3 years ago

5 0

Answer:

The answer is 44

Step-by-step explanation:

You solve it like a regular equation

6*8+4

48-4

44!!!!

Hope this Helps

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PLEASE HELP (Giving Good Points!)

Vinvika [58]

Answer: q=16

Step-by-step explanation:

if we suppose q=16

(q+4)/2=10

$(16+4)/2=10\\20/2=10\\10=10$

7 0

3 years ago

Which is equivalent to 3 cube root 125

aleksklad [387]

Do you mean $3 \sqrt[3]{125}$ or $\sqrt[3]{125}$
remember that $\sqrt[n]{x^m}=x^\frac{m}{n}$
resolve the $\sqrt[3]{125}$ part first $\sqrt[3]{125}=$ $\sqrt[3]{5^3}=$ $5^\frac{3}{3}=$ $5^1=$ $5$

so
$3 \sqrt[3]{125}=3*5=15$ or $\sqrt[3]{125} =5$ not sure which one you mean

7 0

3 years ago

Read 2 more answers

3. My divisor is 8.

Vera_Pavlovna [14]

Answer: 29

Step-by-step explanation:

29 ÷ 8 = 3 remainder: 5

I solved using long division.

7 0

3 years ago

Read 2 more answers

3^x+2=8^x-1 Solve for x.

zubka84 [21]

I assume the equation is supposed to be

$3^{x+2}=8^{x-1}$

Then we can write

$9\cdot3^x=\dfrac18\cdot8^x\implies\left(\dfrac38\right)^x=\dfrac1{72}$

Take the logarithm of base 3/8 on both sides:

$\log_{3/8}\left(\dfrac38\right)^x=\log_{3/8}\dfrac1{72}$

$\implies x\log_{3/8}\dfrac38=-\log_{3/8}72$

$\implies x=-\log_{3/8}72$

- - -

If the equation is actually $3^x+2=8^x-1$ , I'm afraid it cannot be solved exactly.

5 0

3 years ago

Find the dimensions of a rectangle with perimeter 112 m whose area is as large as possible. step 1 if a rectangle has dimensions

Veronika [31]

Please use the solution below:
Let P = perimeter, A = area
As provided above, a = xy and
We know that the formula to solve for the perimeter of a rectangle is P = 2x + 2y. Using the given 112m, we can solve the perimeter using the formula:
112 = 2x + 2y
56 = x + y

x = 56-y or y = 56-x
Let's solve the perimeter in terms of y using the formula below:
A = (56-y)(y)
Find the derivative of A = 56-y^2 to get the value of y.
dA/dy = 56-2y = 0
y = 56/2
y = 28
To find X, substitute the value of y in the equation x = 56 - y.
x = 56 - 28
Therefore, x = 28.
We can conclude that the figure is not a rectangle but a square.

7 0

3 years ago