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Leni [432]
3 years ago
9

6. A wire Il om long has a mass of 187 g. What is the mass of 7 cm of this wire?

Mathematics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

119 g.

Step-by-step explanation:

11 cm has a mass of 187 g

So 1 cm has a mass of 187/11 g

7 cm ...............................  (187/11) * 7

= 17 * 7

=  119 g.

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The period of a periodic function is 8 s . How many cycles does it go through in 30 s ?
kap26 [50]

The number of cycles of the periodic function is 3.75 cycles if the period of a periodic function is 8 s option (G) 3.75 is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

It is given that:

The period of a periodic function is 8 s

From the question:

8n = 30

n = 30/8

n = 3.75 cycles

Thus, the number of cycles of the periodic function is 3.75 cycles if the  period of a periodic function is 8 s option (G) 3.75 is correct.

Learn more about the function here:

brainly.com/question/5245372

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7 0
1 year ago
A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

8 0
3 years ago
If 97 of 200 is 100% then how much of 200 is 112%
pickupchik [31]
To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 112 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 112 is 100%, so we can write it down as 112=100%.
4. We know, that x is 200% of the output value, so we can write it down as x=200%.
5. Now we have two simple equations:
1) 112=100%
2) x=200%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
112/x=100%/200%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 200% of 112

112/x=100/200
(112/x)*x=(100/200)*x - we multiply both sides of the equation by x
112=0.5*x - we divide both sides of the equation by (0.5) to get x
112/0.5=x
224=x
x=224

now we have:
200% of 112=224



●I tried my best I was never good with percentages my least favorite.... Please let me know if you got it wrong. If you do I'm sorry.
3 0
3 years ago
How to find the missing angle of a parallelogram only knowing 1 number?
lesantik [10]
Answer:  
__________________________________________________________
     If you know the measure of the angle of one particular angle, the alternate interior angle that corresponds to said particular angle will have that same measurement.
___________________________________________________________
4 0
3 years ago
There are (4^9)5 ⋅ 4^0 books at the library. What is the total number of books at the library? 4^9 - 4^45 - 4^46 - 1
maria [59]
Exponent rules : (a^m)^n = a^(mn) and a^0 = 1

(4^9)^5 * 4^0 =
4^45 * 1 =
4^45 <==
7 0
3 years ago
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