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zhuklara [117]
2 years ago
6

23 A circular fish pond has an area of 20m 2 Calculate the diameter of the fish pond.

Mathematics
1 answer:
Tju [1.3M]2 years ago
7 0

Answer:

40 · sqrt(pi)/pi I believe

Step-by-step explanation:


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a washer and a dryer cost 659$ combined. The washer costs 91$ less than the dryer, how much was the dryer?  
Darina [25.2K]
W+D=659

W=D-91

---------------------------

(D-91)+D=659

D-91+D=659

2D=750

D=750/2=375

------------------------------

W+375=659

W=284

------------------------------

So the dryer had cost $375 and the washer had cost $284.
7 0
3 years ago
Read 2 more answers
What is x, the distance between points A and A'? 2. 4 units 4. 8 units 13. 6 units 14. 4 units.
adelina 88 [10]

The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

Given that,

The points A (3, -5) and A' (2, -3).

We have to determine,

The distance between point A and A'.

According  to the question,

The distance between two points is determined by using the distance formula.

\rm Distance \ formula = \sqrt{(x_2-x_2) ^2+ (y_2-y_2)^2

Then,

The distance between points A (3, -5) and A' (2, -3) is,

\rm Distance  = \sqrt{(2-3) ^2+ ((-3)-(-5))^2}\\\\ Distance  = \sqrt{(-1) ^2+ (2)^2}\\\\ Distance  = \sqrt{1+4}\\\\Distance = \sqrt{5}\\\\Distance = 2.4 \ units

Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

For more details refer to the link given below.

brainly.com/question/8069952

6 0
2 years ago
Read 2 more answers
I Am A Number That Is Double The Product Of 2 And 7. One Of My Factors Is 7 What Is My Other factor
tatyana61 [14]
If 7 × 2 = 14, then 14 + 14 = 28. So, 7 times 4 equals to 28. You can add 14 + 14 or multiply 7 and 4 to get your answer.
7 0
3 years ago
PLEASE!! HELP!!
anygoal [31]

Answer:

2nd dot from the left (in the 1.7 column)

Step-by-step explanation:

the square root of 3 is 1.73

each interval on that number line goes by one tenths

(1.1, 1.2, 1.3, etc.)

so counting 7 spaces from the number one should land you at 1.7

(the second red dot from the left)

hope i was able to help!

5 0
3 years ago
Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos
crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c)  P(X = 2) is unusual, P(X = 0) is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A number of sucesses x is considered unusually low if P(X \leq x) \leq 0.05 and unusually high if P(X \geq x) \geq 0.05

In this problem, we have that:

Two cans are randomly chosen, so n = 2

Two out of 18 cans are filled with diet coke, so \pi = \frac{2}{18} = 0.11

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that P(X = 2) is unusual, since P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0
3 years ago
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