1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elan Coil [88]
3 years ago
11

Units. Find the other

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

L = 12

Step-by-step explanation:

I didn't really know how to do it I just looked it up lol

You might be interested in
Need help with this What are the like terms in the equation 5x + 3y + 2x + 3z = 27? ASAP
Tatiana [17]

Answer:

c

Step-by-step explanation:

the like terms are 5x and 2x

3 0
3 years ago
Read 2 more answers
Find the equation of the line that<br> is parallel to y = 4x + 1 and<br> contains the point (1, 1).
n200080 [17]

Answer:

y=4x+1

answer= y=4x

Step-by-step explanation:

y=4x+1

1=4(1)+1

1=5

4 0
3 years ago
Read 2 more answers
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

8 0
1 year ago
Consider ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.
LenKa [72]

Answer:- B. No, because the corresponding congruent angles listed are not the included angles.


Explanation:-

Given:- ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.

Now, look at the attachment

We can see that ∠X and ∠C are not included angles by the corresponding equal sides.

⇒ We cannot use SAS postulate to show ΔWXY ≅ ΔBCD .

⇒ B is the right option.

SAS postulate tells the if two sides of a triangle and their included angle is equal to the two sides of a triangle and their included angle of another triangle then the two triangles are congruent.

5 0
3 years ago
Read 2 more answers
I need help!!!!!!<br> Help Needed!!!!
tatiyna

help with what? be sure to put everything you need to say into a question

5 0
3 years ago
Other questions:
  • To you divide fractions, you have to ______ by the reciprocal
    9·2 answers
  • Complete the proof of the Law of Sines/Cosines.
    13·1 answer
  • .......Help Please......
    12·1 answer
  • Anyone? Help please its my final test!!!
    14·1 answer
  • A.3/4-3/10<br><br> Do this for me please and this <br><br> B.3 1/2- 1 1/3
    8·1 answer
  • Find the area of the circle.
    7·2 answers
  • Order the set of integers from greatest to least. {-100, -89, -124, -69, -52}
    9·1 answer
  • Which type of graphs show individual data?
    11·1 answer
  • Math easy help pls asap
    11·1 answer
  • Git Quot Method 8. A landscape architect designs a rectangular garden that is
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!