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valentinak56 [21]
4 years ago
15

7) If AB = 3x - 8 and BC = x + 12, find the value of x.​

Mathematics
1 answer:
Finger [1]4 years ago
4 0

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

In a square ABCD, if AB = (3x-8) and BC = (x+12), find the value of x. Also, find the length of each side of the square.

Note that all sides of a square are equal. Hence AB = BC for the square ABCD.

Given AB = (3x-8) and BC = (x+12), then AB = BC

3x-8 = x+12

collect like terms;

3x-x = 12+8

2x = 20

x = 20/2

x = 10

Substitute x = 10 into any of the side. Using side AB

AB = 3x-8

AB = 3(10)-8

AB = 30-8

AB = 22

BC = x+12

BC = 10+12

BC = 22

<em>Hence x = 10 and the length of each side is 22</em>

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The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
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We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: (2w+33)^2=w^2+(2w+31)^2. Distributing by multiplying we simplify to 4w^2+132w+1089=w^2+4w^2+124w+961. We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have w^2-8w-128=0. The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!

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2x+y=7 for y neeedd help
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Answer:

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Step-by-step explanation:

<u>Solve for y:</u>

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