0.52 because 52/100 is better than 52/1000 and 52/10000
<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
Answer:
336
Step-by-step explanation:
The first year added $18 so just double the lat 2 digits
Answer:
57.50+4x=75.10
x=4.4
So she can use up to 4.4 gigabytes of data
-4c = 12
divide both sides by -4
c = -3
