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SCORPION-xisa [38]
3 years ago
15

Can someone please explain to me how to find the area of this trapezoid?

Mathematics
2 answers:
Makovka662 [10]3 years ago
7 0
The formula for finding a trapezoid's area is:

A = a+b
      ------ x h
         2
So for this, you just have to plug the numbers in.

A = 32 in²
azamat3 years ago
5 0
Area=Base*Base/2(height)
To simplify it, get both of the bases, and multiply them. Then divide the product by 2. Then multiply that answer by the height
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%100 is shown on the following tape diagram. What percent is represented by the entire tape diagram?
maxonik [38]
100% is shown on the diagram
8 0
3 years ago
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What is the value of the expression 2x² – 5x + 6 when<br> x = -2?
Svet_ta [14]

Answer:

24 is correct answer

Step-by-step explanation:

2 {x}^{2}  - 5x + 6 \\  = 2 {( - 2)}^{2}  - 5 \times ( - 2) + 6 \\  = 2 \times 4 + 10 + 6 \\  = 8 + 10 + 6  \\  = 24

hope it helped you:)

3 0
3 years ago
[Supporting Standard: I can find the sum of an infinite series.]
Tanya [424]

Answer:

787.5 is the answer.

Step-by-step explanation:

FOLLOW ME

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4 0
3 years ago
Find two positive numbers satisfying the given requirements. the product is 192 and the sum of the first plus three times the se
Zepler [3.9K]
<h3>Given</h3>

Two positive numbers x and y such that xy = 192

<h3>Find</h3>

The values that minimize x + 3y

<h3>Solution</h3>

y = 192/x . . . . . solve for y

f(x) = x + 3y

f(x) = x + 3(192/x) . . . . . the function we want to minimize

We can find the x that minimizes of f(x) by setting the derivative of f(x) to zero.

... f'(x) = 1 - 576/x² = 0

... 576 = x² . . . . . . . . . . . . multiply by x², add 576

... √576 = x = 24 . . . . . . . take the square root

... y = 192/24 = 8 . . . . . . . find the value of y using the above equation for y

The first number is 24.

The second number is 8.

6 0
3 years ago
with the square root of negative 1 in the numerator (the top) and eight in the demominator (on bottom) what is the answer
AleksAgata [21]
-1^2/8 = 1/8 is the answer
6 0
3 years ago
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