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Leokris [45]
3 years ago
7

The table shows the steps for solving the given inequality for x.

Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

We are given :  -3(4-6x) < x+5.

Solution: -3 is in front of Parenthesis.

We need to multiply -3 by (4-6x).

So, we need to applying distributive property.

On distributing, we get

-12+18x < x+5        (By distributive property)

The reverse operation of addition is subtraction. So we need to subtract x from both sides, we get

-12+18x-x < x-x+5    (By subtraction property of equality).

-12+17x < 5

Now, we need to get rid -12 from left side.

So, we need to apply addition property of equality, we need to add 12 on both sides, we get

-12+12+18x < x+5+12    (By addition property of equality)

17x < 17

We need to get rid 17 from left side. So we need to apply division property of equality.

On dividing both sides by 17, we get

17x/17 < 17/17      (By division property of equality)

x < 1.

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Describe a pattern in each sequence. What are the next two terms of each sequence
Mice21 [21]

Answer:

25

Step-by-step explanation:

you divide each term by 2

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3 years ago
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777dan777 [17]
If we join the Center with different corners of the polygon,we find 10 Isoceles triangle with equal side=9.14cm, Making an angle of 36° between the equal sides.

Area of 1 triangle= a*b*sinC/2
= 9.14*9.14*Sin36°/2
= 9.14*9.14*0.587/2
=24.51 cm^2

Area of 10 triangle= 24.51*10
= 245.1cm^2

6 0
4 years ago
Seven and one-half foot-pounds of work is required to compress a spring 2 inches from its natural length. Find the work required
ella [17]

Answer:

Apply Hooke's Law to the integral application for work: W = int_a^b F dx , we get:

W = int_a^b kx dx

W = k * int_a^b x dx

Apply Power rule for integration: int x^n(dx) = x^(n+1)/(n+1)

W = k * x^(1+1)/(1+1)|_a^b

W = k * x^2/2|_a^b

 

From the given work: seven and one-half foot-pounds (7.5 ft-lbs) , note that the units has "ft" instead of inches.   To be consistent, apply the conversion factor: 12 inches = 1 foot then:

 

2 inches = 1/6 ft

 

1/2 or 0.5 inches =1/24 ft

To solve for k, we consider the initial condition of applying 7.5 ft-lbs to compress a spring  2 inches or 1/6 ft from its natural length. Compressing 1/6 ft of it natural length implies the boundary values: a=0 to b=1/6 ft.

Applying  W = k * x^2/2|_a^b , we get:

7.5= k * x^2/2|_0^(1/6)

Apply definite integral formula: F(x)|_a^b = F(b)-F(a) .

7.5 =k [(1/6)^2/2-(0)^2/2]

7.5 = k * [(1/36)/2 -0]

7.5= k *[1/72]

 

k =7.5*72

k =540

 

To solve for the work needed to compress the spring with additional 1/24 ft, we  plug-in: k =540 , a=1/6 , and b = 5/24 on W = k * x^2/2|_a^b .

Note that compressing "additional one-half inches" from its 2 inches compression is the same as to  compress a spring 2.5 inches or 5/24 ft from its natural length.

W= 540 * x^2/2|_((1/6))^((5/24))

W = 540 [ (5/24)^2/2-(1/6)^2/2 ]

W =540 [25/1152- 1/72 ]

W =540[1/128]

W=135/32 or 4.21875 ft-lbs

Step-by-step explanation:

5 0
3 years ago
Bob earns $10 per hour plus a
Mekhanik [1.2K]

Answer:

C, 10h + 0.15s

Step-by-step explanation:

he earns 10 dollars per hour so 10h

he earns 15% or .15 per sale so .15s

add them together to get 10h + 0.15s

6 0
3 years ago
A 99% confidence interval (in inches) for the mean height of a population is 65.7 &lt; μ &lt; 67.3. This result is based on a sa
Wittaler [7]

Answer:

66.5 -1.976* 0.3065= 65.89

66.5 +1.976* 0.3065= 67.11

And the 95% confidence interval would be givne by (65.89; 67.11)

Step-by-step explanation:

For this case we have a 99% confidence interval for the true mean hegiht givne by:

65.7 \leq \mu \leq 67.3

And we can begin finding the mean with this formula:

\bar X= \frac{65.7 +67.3}{2}= 66.5

Now we can estimate the margin of error:

ME = \frac{67.3-65.7}{2}= 0.8

The sample size for this case is n = 144 then the degrees of freedom are given by:

df = n-1= 144-1=143

And then we can find a critical value for a 99% of confidence and 143 degrees of freedom using a significance level of 0.01 and we got:

t_{\alpha/2}= 2.61

Then the standard error is given by:

SE = \frac{ME}{t_{\alpha/2}}= \frac{0.8}{2.61}= 0.3065

Now we can find the other critical value for 95% of confidence and we got:

t_{\alpha/2}= 1.976

And the new confidence interval would be given by:

66.5 -1.976* 0.3065= 65.89

66.5 +1.976* 0.3065= 67.11

And the 95% confidence interval would be givne by (65.89; 67.11)

3 0
3 years ago
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