<span>(5+2 i)(4-3i) - (5-2yi)(4-3i)
Factorize out (4 -3i)
(4 -3i)( (5 +2i) - (5 -2yi) )
= </span><span><span>(4 -3i)(5 +2i - 5 + 2yi)</span>
= </span><span><span>(4 -3i)(5 - 5 + 2i + 2yi)</span>
= (4 -3i)(2i + 2yi)
= (4 - 3i)(2 + 2y)i. Let's multiply the first two.
</span>
(4 - 3i)(2 + 2y) = 2*(4 -3i) + 2y*(4 - 3i)
= 8 - 6i + 8y - 6yi
= 8 + 8y - 6i - 6yi
(4 - 3i)(2 + 2y)i = (8 + 8y - 6i - 6yi)i Note: i² = -1
= 8i + 8yi - 6i² - 6yi²
= 8i + 8yi - 6(-1) - 6y(-1)
= 8i + 8yi + 6 + 6y
= 6 + 6y + 8i + 8yi
= (6 + 6y) + (8 + 8y)i In the form a + bi
Answer:
My solution is I don't have solutions
Answer:
This isn't that specific enough
Step-by-step explanation:
Answer:
x=-2
Step-by-step explanation:
2x+4-4=0-4
2x=-4
x=-2
Answer:
(2, -6)
Step-by-step explanation:
5n^2+20n-60
(5n+30)(n-2)
5n + 30 = 0
5n = -30
(5n = -30)/5
n = - 6
n - 2 = 0
n = 2
answer: (2, -6)
