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3 years ago

Find the equation of a parabola that opens up and has the following x intercepts (-3,0) and (4,0)

Mathematics

1 answer:

Elenna [48]3 years ago

5 0

The equation of a parabola that opens up and has the following x intercepts (-3,0) and (4,0) is $y=x^{2}-x-12$

<h3><u>Solution:</u></h3>

We have to find the equation of a parabola that opens up and has the following x intercepts (-3, 0) and (4, 0)

x-intercepts of the parabola are (−3, 0) and (4, 0)

So, we can form an equation:

Also x = 4

x – 4 = 0

x – 4 = 0 is another factor of quadratic equation.

The quadratic function is:

$\begin{array}{l}{y=(x+3)(x-4)} \\\\ {y=x^{2}-4 x+3 x-12} \\\\ {y=x^{2}-x-12}\end{array}$

Hence, the equation of the parabola is $y=x^{2}-x-12$

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