All categories

3 years ago

Please help friends with diagram

Mathematics

1 answer:

natta225 [31]3 years ago

3 0

Given:

The data values are 13, 6, 12, 9, 11, 14, 2, 8, 18, 16, 9, 12, 17, 11, 19, 6, 7, 12, 22, 21, 18, 1, 8, 12, 18.

To find:

The frequency distribution table for given data values by using the class intervals 0-5, 5-10,..., and draw a histogram.

Solution:

The frequency distribution table for given data values is:

Intervals Data values Frequency

0-5 2,1 2

5-10 6,9,8,9,6,7,8 7

10-15 13,12,11,14,12,11,12,12 8

15-20 18,16,17,19,18,18 6

20-25 22,21 2

To draw the histogram, intervals must be represented on the x-axis and frequencies represented on the y-axis as shown below:

You might be interested in

Which expression shows the result of applying the distributive property to 12(5y+4) ?

brilliants [131]

<span>12(5y+4)
= 12(5y) + 12(4)
= 60y + 48

hope it helps</span>

6 0

3 years ago

Find the product of the complex numbers (-5+ 8i) and (3 - 8i)

Liula [17]

Answer: 49+64i

Step-by-step explanation:

Concept to know:

i=√-1

i²=-1

i³=-i

$i^{4}$ =1

-------------------------------------

(-5+8i)(3-8i)

=-15+40i+24i-64i²

=-15+64i-64i²

=-15+64i+64 (remember, i²=-1)

=49+64i

Hope this helps!! :)

Please let me know if you have any question or need further explanation

7 0

3 years ago

Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona

andrey2020 [161]

Answer:

a. v.v' = v₁v₂ - v₁v₂ = 0 b. (20, -21)/29 and (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' = (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

= v₁v₂ - v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0

3 years ago

Stephanie found a sweater on sale for $12.88. The original price of the sweater was $44.95. About how much did she save on the s

rusak2 [61]

Answer:

$32.07

ROUNDING ANSWER : $32

Step-by-step explanation:

you would subtract $44.95 -$12.88 which would give you $32.07

since you are rounding your answer would be $32

Hope this helps

8 0

3 years ago

2. What is the width of this ornament if the volume is 2,226.09 cm^3?

finlep [7]

Answer:

C. 20.10

Step-by-step explanation:

V=4/3r^3

5 0

3 years ago