Here's number 5. If you need more explanation just let me know.
Please help friends with diagram
1 answer:
Given:
The data values are 13, 6, 12, 9, 11, 14, 2, 8, 18, 16, 9, 12, 17, 11, 19, 6, 7, 12, 22, 21, 18, 1, 8, 12, 18.
To find:
The frequency distribution table for given data values by using the class intervals 0-5, 5-10,..., and draw a histogram.
Solution:
The frequency distribution table for given data values is:
Intervals Data values Frequency
0-5 2,1 2
5-10 6,9,8,9,6,7,8 7
10-15 13,12,11,14,12,11,12,12 8
15-20 18,16,17,19,18,18 6
20-25 22,21 2
To draw the histogram, intervals must be represented on the x-axis and frequencies represented on the y-axis as shown below:
You might be interested in
Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
Answer: 0.82
Step-by-step explanation:
The probability of the computer not containing neither a virus nor a worm is expressed as P(∩
) , where P(
) is the probability that the event V doesn't happen and P(
) is the probability that the event W doesn't happen.
P()= 1-P(V) = 1-0.17 = 0.83
P()=1-P(W) = 1-0.05 = 0.95
Since and
aren't mutually exclusive events, then:
P(∪
) = P(
) + P(
) - P(
∩
)
Isolating the probability that interests us:
P(∩
)= P(
) + P(
) - P(
∪
)
Where P(∪
) = 1 - 0.04 = 0.96
Finally:
P(∩
) = 0.83 + 0.95 - 0.96 = 0.82