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3 years ago

Need more urgent help plz

Mathematics

1 answer:

NemiM [27]3 years ago

3 0

Answer:

the answer is BBBB

Step-by-step explanation:

IT IS BBBB... i think

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Which inequality is represented by this graph?<br> f(0, 1)<br> (5,0)

Novosadov [1.4K]

Answer:

I would say C.

Step-by-step explanation:

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3 years ago

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In ΔDEF, the measure of ∠F=90°, EF = 2.3 feet, and FD = 2.9 feet. Find the measure of ∠D to the nearest tenth of a degree.

Phoenix [80]

Answer:

$\theta=38.42 \textdegree$

Step-by-step explanation:

From the question we are told that:

Angle of F $\angle F=90 \textdegree$

Length of $EF = 2.3 feet,$

Length of $FD= 2.9 feet,$

Generally the equation for Angle D $\theta$ is mathematically given by

Since $\angle F=90$ .The triangle is a right angle Triangle

Therefore

$tan \theta=\frac{EF}{FD}$

$tan \theta=\frac{2.3}{2.9}$

$\theta=tan^{-1} 0.793$

$\theta=38.42 \textdegree$

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3 years ago

Find equivalent fraction with a common denominator and order from least to greatest

nika2105 [10]

The fractions would be in order-
3/10, 1/2, 4/5
Because if you change each fraction to a denominator of 10, the numbers will be 3/10, 5/10, and 8/10

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3 years ago

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What is this I need to know now

katen-ka-za [31]

3x2 is six. If you do that across, you would get 6/6 for both. 6/6 - 6/6 is how much?

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4 years ago

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A random sample of 1000 people was taken. Four hundred fifty of the people in the sample favored Candidate A. The 95% confidence

KatRina [158]

Answer:

The 95% confidence interval would be given (0.419;0.481).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

X=450 represent the people in the sample favored Candidate A

$\hat p=\frac{450}{1000}=0.45$ estimated proportion of people in the sample favored Candidate A

$\alpha=0.05$ represent the significance level

Confidence =0.95 or 95%

p= population proportion of people in the sample favored Candidate A

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.45 - 1.96 \sqrt{\frac{0.45(1-0.45)}{1000}}=0.419$

$0.45 + 1.96 \sqrt{\frac{0.45(1-0.45)}{1000}}=0.481$

And the 95% confidence interval would be given (0.419;0.481).

We are confident (95%) that about 41.9% to 48.1% of the people are favored Candidate A.

3 0

3 years ago