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shusha [124]
2 years ago
15

Factorise completely;y(ay-x)+x(y-ax)​

Mathematics
1 answer:
Kay [80]2 years ago
5 0

Answer:

ay2 - xy + xy - ax2

ay2- ax2

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Question Category: Solving Quadratic Equations by Factoring Select the correct answer. Find the solution(s) for x in the equatio
Novay_Z [31]

Answer: x = 4; x = 5

Step-by-step explanation:

The directions specify to solve by factoring

x^2 - 9x + 20 = 0

To factor, find two numbers that add to -9 and multiply to 20

-5 and -4 work

-5 + (-4) = -9

-5 * -4 = 20

(x - 4)(x - 5) = 0

x = 4, x =5

6 0
3 years ago
What is 1 1/3 as a improper fraction
Mumz [18]
Okay so for this all you have to do is add 1 to 1/3.

However, to do this you first need to convert 1 into a fraction.

1 = 3/3
3/3 + 1/3 = 4/3

Hope this helps :)
8 0
2 years ago
Georgia’s scores in six subjects are 89, 75, 92, 68, 78, 75, and 80. If she finds a single value that summarizes all the values
posledela
It would be mean. The mean is the average that is you are looking for, since she wants a summerization of all the values in the data set. To find the mean (average) add all the numbers and then divide by the amount of numbers.
5 0
3 years ago
What is the perimeter of triangle ABC? Round each step to the nearest tenth. Please help me
Ad libitum [116K]

I would use the pythagorean theorem to find the lengths of each side. a² + b² = c².

Side AB is one we're looking for. If you make other right triangle with that same side you can see that one length is 4 and the other is 3. So, 4² + 3² = c² → 25 = c² → 5 = c. Side AB is length 5.

Side AC is another. Do the same with that side and you get that one length is 4 and the other is 3. (This is the same one as above) so side AC is length 5.

Side BC is the last one. One of the lengths is 1 and the other is 1 → 1² + 1² = c² → 2 = c² → 1.414213562 = c so side BC is approximately length 1.41.

Add each length up and you get a perimeter of roughly 11.4

8 0
3 years ago
Can someone help me? Thanks!
scZoUnD [109]
3 to the -3 power.. ...
7 0
3 years ago
Read 2 more answers
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