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Fudgin [204]
3 years ago
14

The system of equation y=-2x+3 and y=x is graphed.what is the solution to the system of equations

Mathematics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

  (x, y) = (1, 1)

Step-by-step explanation:

Using the second equation to substitute for y in the first equation, we have ...

  x = -2x +3

  3x = 3 . . . . . . . add 2x

  x = 1 . . . . . . . . .divide by 3

  y = x = 1

The solution is (x, y) = (1, 1).

_____

If you have the graph, you can read the solution from it as the coordinates of the point where the lines cross.

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F left parenthesis x right parenthesis equals 9 x cubed plus 2 x squared minus 5 x plus 4 and g left parenthesis x right parenth
Jet001 [13]
The answer is 2x(2x²+x+1).

When we subtract polynomials we combine like terms:
(9x³+2x²-5x+4)-(5x³-7x+4)

9x³-5x³=4x³
2x²- 0 = 2x²
-5x--7x=-5x+7x=2x
4-4=0

This gives us 
4x³+2x²+2x

Each of these is divisible by 2, and each has an x, so we factor those out:
2x(                        )

4x³/2x = 2x²:
2x(2x²                   )

2x²/2x=x:
2x(2x²+x               )

2x/2x = 1:
2x(2x²+x+1)
3 0
3 years ago
In the following equations <br>solve for x<br>2(x - 1) = 16<br>(3×1) - (5=86) -10​
lara31 [8.8K]

Step-by-step explanation:

2(X-1)=16

2X-2=16

2X=16+2

X=18÷2

X=9

I don't understand (3×1)-(5=86)-10

I think it is wrong or sth I don't know!

6 0
3 years ago
The number of students enrolled at a college is 18,000 and grows 6% each year. part c: to find the number of students enrolled a
Alex777 [14]
18000 x 6/100 (Because 6%)
1080 each year.
Hope I helped!
8 0
3 years ago
5. Consider a cylindrical flowerpot with a radius 6 cm and a height of 11.5 cm. Calculate the lateral surface area of the painte
Nina [5.8K]

Answer: 660 cm²

Step-by-step explanation:

Surface area of a cylinder = 2πr² ± 2πrh = 2πr ( r + h )

π = 22/7

r = 6 cm

h = 11.5 cm

Lateral surface area = 2 x 22/7 x 6 ( 6 + 11.5 )

= 660 cm²

8 0
3 years ago
The following dotplot shows the centuries during which the 11 castles whose ruins remain in Somerset, England were constructed.
nasty-shy [4]

Taking into account the rule 1.5 IQR, there aren't high outliers in the displayed data set.

Calculation of the Interquartile Range and the rule 1.5 IQR.

To calculate the Interquartile Range IQR, you must subtract the value of the first quartile Q1, to the third quartile Q3, as you can see in the formula below:

IQR = Q3 - Q1

Using the five-number summary, you can replace the formula:

IQR = 17 - 13

IQR = 4

Before to apply the rule 1.5 IQR, you must multiply the IQR by 1.5:

4 * 1.5 = 6

Now, to apply the rule you must add the value obtained (6), to the third quartile (17), if any data is over this, theoretically it's an outlier:

17 + 6 = 23 (As you do not have any data over this value, it is identified that there are no outliers in the upper section).

Finally, you must subtract the value obtained (6) to the first quartile (13), if any data is under this, theoretically it's an outlier:

13 - 6 = 7 (Since you don't have any castle data built before this century, there wouldn't be any theoretically outliers either).

By this reason, using the rule of 1.5 IQR, you can see there aren't outliers in the displayed data set.

brainliest please if correct.

3 0
2 years ago
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