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sertanlavr [38]
2 years ago
5

How many solutions does the equation y + 3y - 6 = -2 + 4y + 4 have?

Mathematics
1 answer:
mestny [16]2 years ago
7 0

\huge{ \mathrm{ \underline{question  : }}}

How many solutions does the equation have ?

y + 3y - 6 = -2 + 4y + 4

\huge{ \mathcal{  \underline{ Answer \:  \:  ✓ }}}

The given equation has

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B. \boxed{No \: \: solution}

\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\

\#TeeNForeveR

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An isosceles trapezoid has base angles 45 and bases of lengths 9 and 15 the area pf the trapezoid is
Nadusha1986 [10]
Tangent 45 = height / 3
height = 3 * tan (45)
height = 3 * 1
height = 3

<span>Trapezoid area = ((sum of the bases) ÷ 2) • height
</span>
<span>Trapezoid area =  (9 + 15) /2 * height

</span><span>Trapezoid area =  12 * 3

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7 0
3 years ago
How many 3-digit numbers can you write using only the digits 1 and 2?
defon
For the first digit, you have two possible choices: 1 or 2. For *each* of those choices, you can choose 1 or 2 for the second digit in the number, and for each of *those*, you can choose 1 or 2 for the third digit of the number.

That’s 2 * 2 * 2 or 8 possible 3-digit numbers you can make with the digits 1 and 2.
4 0
3 years ago
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8 0
3 years ago
Which table represents points on the graph of h(x) = RootIndex 3 StartRoot negative x + 2 EndRoot?
Alex_Xolod [135]

Answer:

Table 3

Step-by-step explanation:

The third one.

We have the function

                               h(x) = \sqrt[3]{-x+2}

Now we will insert values of x in that definition o h(x) and see if the values we obtain match the corresponding y values in the table:

                  h(-6) = \sqrt[3]{-(-6)+2}= \sqrt[3]{6+2}= \sqrt[3]{8} = 2\\h(1) = \sqrt[3]{-1+2}= \sqrt[3]{1}= 1\\h(2) = \sqrt[3]{-2+2}= \sqrt[3]{0}= 0\\h(3) = \sqrt[3]{-3+2}= \sqrt[3]{1}= 1\\h(10) = \sqrt[3]{-10+2}= \sqrt[3]{-8}= -2

We can see that the values match the table 3, so the table 3 represents points on the graph of h(x)

3 0
2 years ago
Read 2 more answers
Which function passes through the points (2,3) and (4,4)?
Pie
A(2;3), B(4;4)
y=ax+b
a=\dfrac{4-3}{4-2}=\dfrac{1}{2}
3=\dfrac{1}{2}*2+b
3=1+b
b=2

y=\dfrac{1}{2}x+2

:)
6 0
2 years ago
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