Question

This is my third time posting this bc i kept getting the wrong answer please help me

Answer 1

Answer:

B

Step-by-step explanation:

So we have:

$\frac{x^{\frac{2}{3}}}{y^{\frac{-3}{4}}}$

First, we recall that we can switch an exponent from the denominator to the numerator if we multiply the exponent by -1 and vice versa. Therefore:

$=x^{\frac{2}{3}}}\cdot {y^{\frac{3}{4}}$

Now, use the following property:

$a^{x/n}=\sqrt[n]{a^x}$

Therefore:

$x^{\frac{2}{3}}=\sqrt[3]{x^2}$

And:

$y^{\frac{3}{4}}=\sqrt[4]{y^3}$

And so together:

$=x^{\frac{2}{3}}}\cdot {y^{\frac{3}{4}}\\=\sqrt[3]{x^2}\cdot\sqrt[4]{y^3}$

Our answer is B :)